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3 years ago

15

the width of a rectangle is twice as long as the length. if the length is increased by 50% and the width is decreased by 20%, th

e perimeter becomes 248. find the width and length of the original rectangle.

1 answer:

evablogger [386]3 years ago

8 0

Answer:

Width: 160

Length: 80

Step-by-step explanation:

Width = 2x and length = x

X + 0.5x + 2x - 0.4x = 248

3.1x = 248

X = 248/3.1

X = 80

Width = (2)(80) and length = 80

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3 years ago

<img src="https://tex.z-dn.net/?f=%5Csf%20%5Csqrt%7B12%7D%20%5Ctimes%20%5Csqrt%7B12%7D" id="TexFormula1" title="\sf \sqrt{12} \t

Darina [25.2K]

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$\sqrt{12} \times\sqrt{12}$

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