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3 years ago

Which of the following metals will liberate hydrogen from dilute HCL? A. Ag B.Au C.Hg D.Sn

Chemistry

1 answer:

ollegr [7]3 years ago

5 0

Answer:

ag and au are sure not to react. but hg and sn might or might not

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Pure magnesium metal is often found as ribbons and can easily burn in the presence of oxygen. When 3.97 g of magnesium ribbon bu

taurus [48]

Answer:

The balanced chemical equation is given as:

$2Mg(s)+O_2(g)\rightarrow 2MgO(s)$

Explanation:

When magnesium metal burns in presence of oxygen it gives white color powdered compound called magnesium oxide.

The balanced chemical equation is given as:

$2Mg(s)+O_2(g)\rightarrow 2MgO(s)$

According to reaction, 2 moles of magnesium metal when reacts with 1 mole of oxygen gas it gives 2 moles of solid magnesium oxide.

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3 years ago

Which has a greater amount of particles, 1.00 mole of hydrogen (H) or 1.00 moles of oxygen(0)?

Bas_tet [7]

Answer:

Both have the same amount of particles.

Explanation:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ particles.

This implies that 1 mole of Hydrogen contains 6.02×10²³ particles. Also, 1 mole of oxygen contains 6.02×10²³ particles.

Thus, 1 mole of Hydrogen and 1 mole of oxygen contains the same number of particles.

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3 years ago

Which of the following statements best describes a difference between mechanical waves and electromagnetic waves?

kipiarov [429]

The correct answer is the 3rd one

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3 years ago

Give two reasons why scientists create models to study atoms.

mariarad [96]

IT will be easy to know how chemical reactions occur
It will helps to know the fundamental particles of an atom

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3 years ago

A piece of unknown metal with mass 30 g is heated to 110.0 °C and dropped into 100.0 g of water at 20.0 °C. The final temperatur

Ymorist [56]

<u>Answer:</u> The specific heat of metal is 0.821 J/g°C

<u>Explanation:</u>

When metal is dipped in water, the amount of heat released by metal will be equal to the amount of heat absorbed by water.

$Heat_{\text{absorbed}}=Heat_{\text{released}}$

The equation used to calculate heat released or absorbed follows:

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$ ......(1)

where,

q = heat absorbed or released

$m_1$ = mass of metal = 30 g

$m_2$ = mass of water = 100 g

$T_{final}$ = final temperature = 25°C

$T_1$ = initial temperature of metal = 110°C

$T_2$ = initial temperature of water = 20.0°C

$c_1$ = specific heat of metal = ?

$c_2$ = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

$30\times c_1\times (25-110)=-[100\times 4.186\times (25-20)]$

$c_1=0.821J/g^oC$

Hence, the specific heat of metal is 0.821 J/g°C

8 0

3 years ago

Which of the following metals will liberate hydrogen from dilute HCL? A. Ag B.Au C.Hg D.Sn​

Which of the following metals will liberate hydrogen from dilute HCL? A. Ag B.Au C.Hg D.Sn