The equilibrium constant for the following reaction: H2(g) + Br2(g) ↔ 2HBr (g) is 1.65 x 103 at a certain temperature. Find the equilibrium pressure of HBr if 7.10 atm of HBr is introduced into a sealed container at this temperature.
1 answer:
Answer:
6.97 atm was the equilibrium pressure of HBr .
Explanation:
The value of the equilibrium constant =
Initially:
0 0 7.10 atm
At equilibrium
x x (7.10-2x)
The expression of equilibrium constant can be written as:
Solving for x:
x = 0.065
Partial pressure of HBr at equilibrium :(7.10 - 2 × 0.065) atm = 6.97 atm
6.97 atm was the equilibrium pressure of HBr .
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