Answer:
density, yield strength, elasticity, Ductility, toughness, fatigue limit and corrosion resistance
0.1033 moles of oxygen is needed to completely react with 9.5 G of Na.
<u>Answer:</u> The products of the given chemical equation are 
<u>Explanation:</u>
Protonation equation is defined as the equation in which protons get added in the substance.
The chemical equation for the protonation of carbonate ion in the presence of water follows:
By Stoichiometry of the reaction:
1 mole of carbonate ion reacts with 1 mole of water to produce 1 mole of hydrogen carbonate ion and 1 mole of hydroxide ion
Hence, the products of the given chemical equation are
To find out the maximum amount of N2H4 that can be prepared, we must determine which reactant is the controlling factor first. Controlling factor is the reactant that is converted completely during the reaction. Therefore we must first find out the moles of the each reactant (mass/molar mass).
Moles of N2 = 14 g/(28 g/mole) = 0.5 mole
Moles of H2 = 28 g/(2 g/mole) = 14 mole
Because the reaction ratio between N2 and H2 is 1:2, for a complete reaction of 0.5 moles N2, 1 mole H2 is needed. Clearly there are excess amount H2 present. So N2 is the controlling factor.
The ratio between N2 and N2H4 is 1:1, so the maximum moles of N2H4 generated from the reaction is also 0.5 mole. The maximum mass of N2H4 is 0.5 mole * 32 g/mole = 16 g.
