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3 years ago

Which of these cars traveled faster during time interval please show solution

Engineering

1 answer:

Mazyrski [523]3 years ago

3 0

Answer:

I think D is correct

Explanation:

C is decreasing function, probably worst

A is arctan -> in radian, the rate of increasing is very slow-> second worst

B(14) = ln(9*14) = 4.8

D(14) = sqrt(8+14^2)=14.2

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Which list ranks these jobs in the STEM career cluster based on the years of schooling required, from the most to least?

shutvik [7]

Answer:

yes it's C

Explanation:

3 0

3 years ago

Read 2 more answers

If OSHA determines that an employer's response to a non-formal complaint is adequate, what options does the employee filing the

Anuta_ua [19.1K]

Fill it out without telling ur employer as that may cause backlash and have an osha certified employee come check out ur work or job site

4 0

3 years ago

A packet weighs 40kg in air but when it is totally submerged into a 1mx1m square tank the weight of the packet is only 18kg. How

Irina18 [472]

Answer:

water rise = 22 mm

Explanation:

weight of packet IN AIR = 40 *9.81 =392.4 N

weight of packet IN WATER= 18 *9.81 =176.58 N

by Archimedi's principle

difference in weight = weight of displaced water

w_a - w_w = \rho_w v_d g

392.4 - 176.58 = 1000* v_d* 9.81

v_d = 0.022 m^3

v_d = A*H_rise

0.022 =1*H_rise

H_rise = 0.022 m = 22 mm

water rise = 22 mm

5 0

3 years ago

Think about all the things we have investigated in class so far this semester. Identify three examples of climate-related aspect

Free_Kalibri [48]

Answer:

1) the mean surface temperature of earth.

2) precipitation and sunshine

3) air and wind movement.

6 0

3 years ago

A completely reversible heat pump produces heat at a rate of 300 kW to warm a house maintained at 24 °C. The exterior air, which

trapecia [35]

Answer:

No.

Explanation:

The Coefficient of Performance of the reversible heat pump is determined by the Carnot's cycle:

$COP_{HP} = \frac{T_{H}}{T_{H}-T_{L}}$

$COP_{HP} = \frac{297.15\,K}{297.15\,K-280.15\,K}$

$COP_{HP} = 3.339$

The power required to make the heat pump working is:

$\dot W = \frac{300\,kW}{3.339}$

$\dot W = 89.847\,kW$

The heat absorbed from the exterior air is:

$\dot Q_{L} = 300\,kW - 89.847\,kW$

$\dot Q_{L} = 210.153\,kW$

According to the Second Law of Thermodynamics, the entropy generation rate in a reversible cycle must be zero. The formula for the heat pump is:

$\frac{\dot Q_{L}}{T_{L}} - \frac{\dot Q_{H}}{T_{H}} + \dot S_{gen} = 0$

$\dot S_{gen} = \frac{\dot Q_{H}}{T_{H}} - \frac{\dot Q_{L}}{T_{L}}$

$\dot S_{gen} = \frac{300\,kW}{297.15\,K}-\frac{210.153\,kW}{280.15\,K}$

$\dot S_{gen} = 0.259\,\frac{kW}{K}$

Which contradicts the reversibility criterion according to the Second Law of Thermodynamics.

5 0

3 years ago