Answer:
a) ![m=0.17kg/s](https://tex.z-dn.net/?f=m%3D0.17kg%2Fs)
b) ![Ma=0.89](https://tex.z-dn.net/?f=Ma%3D0.89)
Explanation:
From the question we are told that:
Pressure ![P=60kPa](https://tex.z-dn.net/?f=P%3D60kPa)
Diameter ![d=3cm](https://tex.z-dn.net/?f=d%3D3cm)
Generally at sea level
![T_0=288k\\\\\rho_0=1.225kg/m^3\\\\P_0=101350Pa\\\\r=1.4](https://tex.z-dn.net/?f=T_0%3D288k%5C%5C%5C%5C%5Crho_0%3D1.225kg%2Fm%5E3%5C%5C%5C%5CP_0%3D101350Pa%5C%5C%5C%5Cr%3D1.4)
Generally the Power series equation for Mach number is mathematically given by
![\frac{p_0}{p}=(1+\frac{r-1}{2}Ma^2)^{\frac{r}{r-1}}](https://tex.z-dn.net/?f=%5Cfrac%7Bp_0%7D%7Bp%7D%3D%281%2B%5Cfrac%7Br-1%7D%7B2%7DMa%5E2%29%5E%7B%5Cfrac%7Br%7D%7Br-1%7D%7D)
![\frac{101350}{60*10^3}=(1+\frac{1.4-1}{2}Ma^2)^{\frac{1.4}{1.4-1}}](https://tex.z-dn.net/?f=%5Cfrac%7B101350%7D%7B60%2A10%5E3%7D%3D%281%2B%5Cfrac%7B1.4-1%7D%7B2%7DMa%5E2%29%5E%7B%5Cfrac%7B1.4%7D%7B1.4-1%7D%7D)
![Ma=0.89](https://tex.z-dn.net/?f=Ma%3D0.89)
Therefore
Mass flow rate
![\frac{\rho_0}{\rho}=(1+\frac{1.4-1}{2}(0.89)^2)^{\frac{1.4}{1.4-1}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Crho_0%7D%7B%5Crho%7D%3D%281%2B%5Cfrac%7B1.4-1%7D%7B2%7D%280.89%29%5E2%29%5E%7B%5Cfrac%7B1.4%7D%7B1.4-1%7D%7D)
![\frac{1.225}{\rho}=(1+\frac{1.4-1}{2}(0.89)^2)^{\frac{1.4}{1.4-1}}](https://tex.z-dn.net/?f=%5Cfrac%7B1.225%7D%7B%5Crho%7D%3D%281%2B%5Cfrac%7B1.4-1%7D%7B2%7D%280.89%29%5E2%29%5E%7B%5Cfrac%7B1.4%7D%7B1.4-1%7D%7D)
![\rho=0.848kg/m^3](https://tex.z-dn.net/?f=%5Crho%3D0.848kg%2Fm%5E3)
Generally the equation for Velocity at throat is mathematically given by
)
Where
![T_e=\frac{P_e}{R\rho}\\\\T_e=\frac{60*10^6}{288*0.842\rho}](https://tex.z-dn.net/?f=T_e%3D%5Cfrac%7BP_e%7D%7BR%5Crho%7D%5C%5C%5C%5CT_e%3D%5Cfrac%7B60%2A10%5E6%7D%7B288%2A0.842%5Crho%7D)
![T_e=248](https://tex.z-dn.net/?f=T_e%3D248)
Therefore
![V=0.89(1.4*288\sqrt{248})\\\\V=284](https://tex.z-dn.net/?f=V%3D0.89%281.4%2A288%5Csqrt%7B248%7D%29%5C%5C%5C%5CV%3D284)
Generally the equation for Mass flow rate is mathematically given by
![m=\rho*A*V](https://tex.z-dn.net/?f=m%3D%5Crho%2AA%2AV)
![m=0.84*\frac{\pi}{4}*3*10^{-2}*284](https://tex.z-dn.net/?f=m%3D0.84%2A%5Cfrac%7B%5Cpi%7D%7B4%7D%2A3%2A10%5E%7B-2%7D%2A284)
![m=0.17kg/s](https://tex.z-dn.net/?f=m%3D0.17kg%2Fs)
Answer:
2750
Explanation:
The number of windings and the voltage are proportional.
__
Let n represent the number of windings to produce 110 Vac. Then the proportion is ...
n/110 = 300,000/12,000
n = 110(300/12) = 2750 . . . . multiply by 110
2750 windings would be needed to produce 110 Vac at the output.
Answer:
have you heard of gnoogle?
Explanation:have you heard of goongle?
Answer:
6.5 × 10¹⁵/ cm³
Explanation:
Thinking process:
The relation ![N_{o} = N_{i} * \frac{E_{f}-E_{i} }{KT}](https://tex.z-dn.net/?f=N_%7Bo%7D%20%3D%20N_%7Bi%7D%20%2A%20%5Cfrac%7BE_%7Bf%7D-E_%7Bi%7D%20%20%7D%7BKT%7D)
With the expression Ef - Ei = 0.36 × 1.6 × 10⁻¹⁹
and ni = 1.5 × 10¹⁰
Temperature, T = 300 K
K = 1.38 × 10⁻²³
This generates N₀ = 1.654 × 10¹⁶ per cube
Now, there are 10¹⁶ per cubic centimeter
Hence, ![N_{d} = 1.65*10^{16} - 10^{16} \\ = 6.5 * 10^{15} per cm cube](https://tex.z-dn.net/?f=N_%7Bd%7D%20%20%3D%201.65%2A10%5E%7B16%7D%20%20-%2010%5E%7B16%7D%20%5C%5C%20%20%20%20%20%20%20%20%20%20%20%3D%206.5%20%2A%2010%5E%7B15%7D%20per%20cm%20cube)
Answer: speaks Portuguese
Eu disse a todos a tradução para que possam te ajudar
Explanation: Y’all can help I have no idea
QUESTION 13. Explain the use of quotation marks in the excerpt "I will give each of you
seed. The one who will bring me the most beautiful flower within six months will be chosen but
wife and the future empress of China. ".
QUESTION 14. The palace servant considered the idea of her daughter attending the celeb
organized by the prince of the region, a foolish idea, a madness. This is an OP
Do you agree with this opinion of the character? Justify your answer.