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larisa86 [58]
3 years ago
10

Study this chemical reaction:

Chemistry
1 answer:
photoshop1234 [79]3 years ago
4 0

Answer:

The oxidation reaction: Ni → Ni⁴⁺ + 4e.

The reduction reaction: 2Cl₂ + 4e → 4Cl⁻.

Explanation:

  • The mentioned reaction: <em>Ni + 2Cl₂ → NiCl₄.</em>
  • It is an oxidation-reduction reaction comes from two half reactions.

<em>The oxidation reaction:</em> in it Ni losses 4 electrons and is oxidized to Ni⁴⁺ according to the reaction:

<em>Ni → Ni⁴⁺ + 4e.</em>

<em></em>

<em>The reduction reaction: </em>every molecule of Cl₂ will gain 2 electrons and is reduced to 2Cl⁻ according to the reaction:

<em>2Cl₂ + 4e → 4Cl⁻.</em>

<em></em>

  • The summation of the two-half reactions will give the reaction:

<em>Ni + 2Cl₂ → NiCl₄.</em>

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Answer:

The new equilibrium total pressure will be  increased to one-half to initial total pressure.

Explanation:

From the information given :

The equation of the reaction can be represented as;

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From above equation:

2 moles of sulphur dioxide reacts with 1 mole of oxygen  (i.e 2 moles +1 mole  =3 moles ) to give 2 moles of sulphur trioxide

So; suppose the volume of this system is compressed to one-half its initial volume and then equilibrium is reestablished.

So if this process takes place ; the equilibrium will definitely shift to the side with fewer moles , thus the equilibrium will shift to the right. As such; there is increase in pressure.

Let the total pressure at the initial equilibrium be P_1

and the total pressure at the final equilibrium be P_2

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Thus;

P ∝  1/V

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From the foregoing; since the volume is decreased to one- half to initial Volume; then ,

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also;

Thus ;

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3 P_1 V_1 = 2 P_2 V_1

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From ;

P_1V_1 = P_2V_2

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Explanation:

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