Answer:
Explanation:
Calories to be burnt = 3500 - 2500 = 1000 Cals .
Efficiency of conversion to mechanical work is 25 % .
Work needed to burn this much of Cals = 1000 x 100 / 25 = 4000 Cals.
4000 Cals = 4.2 x 4000 = 16800 J .
Work done in one jump = kinetic energy while jumping
= 1/2 m v²
= .5 x 70 x 3.3²
= 381.15 J .
Number of jumps required = 16800 / 381.15
= 44 .
Given:
Therefore, the acceleration is,
<h3>
Explain Acceleration?</h3>
An object's rate of changing its velocity is known as its acceleration, which is a vector quantity. If an object's velocity is changing, it is accelerating. When anything moves faster or slower in a straight line, it is said to have been accelerated. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.
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Based on your problem, what you are looking for is the quantity of heat. To solve for it, you will need this formula:
Q = mc(T2-T1)
Where: Q = Quantity of heat
m = mass of the substance
c = Specific heat
T2 = Final temperature
T1 = Initial temperature
Now the specific heat of water is 4.184 J/(g°C), meaning that is how much energy is required to raise the temperature of 1g of liquid water by 1 degree Celsius.
Since your mass is in kilograms, let us convert that into grams, which will be equal to 50,000 grams. Now we can put our given into the equation:
Q = mc(T2-T1)
= 50,000g x 4.184 J/(g°C) x (80°C - 45°C)
= 50,000 g x 4.184 J/(g°C) x 35°C
= 7,322,000 J or 7,322 kJ or 7.322 MJ
<span>Under velocity would be, change in displacement over change in time, and units m/s. Under acceleration would be, Change in velocity over change in time, and units m/s^2. Under Both would be rate of change and can be positive or negative.</span>
