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IrinaVladis [17]
2 years ago
15

When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance b

etween them, you are obeying which law?
Physics
1 answer:
yuradex [85]2 years ago
7 0

When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, we are obeying Newton's law of universal gravitation.

<h3>Newton's law of universal gravitation</h3>

Newton's law of universal gravitation states that the force of attraction between two masses in the universe is directly proportional to the product of the masses and inversely proportional to the the square of the distance between them.

The mathematical interpretation of the above law is

  • F ∝Mm/r²

Removing the proportionality sign,

  • F = GMm/r².

Where:

  • F = Force of attraction
  • G = Gravitational constant
  • M = Bigger mass
  • m = Smaller mass
  • r = Distance between the masses.

From the above, When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, we are obeying Newton's law of universal gravitation.

Learn more about Newton's law of universal gravitation here: brainly.com/question/9373839

#SPJ12

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Consider a cloudless day on which the sun shines down across the United States. If 2073 kJ of energy reaches a square meter ( m
Mnenie [13.5K]

The total amount of energy per hour is 2.039\cdot 10^{16} kJ

Explanation:

In this problem we are told that the amount of energy reaching a square meter in the United States per hour is

E_1 = 2073 kJ

The total surface area of the United States is

A=9.834\cdot 10^6 km^2

And converting into squared metres,

A=9.834\cdot 10^6 \cdot 10^6 = 9.834\cdot 10^{12} m^2

Therefore, the total energy reaching the entire United States per hour is given by:

E=AE_1 = (9.834\cdot 10^{12})(2073)=2.039\cdot 10^{16} kJ

Learn more about energy and power:

brainly.com/question/7956557

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5 0
3 years ago
The magnitude of vector λa is 5. Find the value of λ, if: a = (−6, 8)
Nata [24]

Given :

\:  \:

  • \color{pink}{\rm \: The \:magnitude \:of \:vector\: λa\: is \:  {\bold5\:}}

\:

  • \color{green}{\rm \: a = (−6, 8)}

\:

To Find :

\:  \:

  • \orange{ \rm\: value \:  of \:  \bold{ λ \: }}

\:  \:

\rm \: The \:  magnitude \:  of \:  the  \: vector  \: a  \: is  \:  ||a|| = \sqrt{(-6)^2+ 8^2)}  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    \:  \:  \rm = \sqrt{( 36+64)} \\ \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:\:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:\:\:   \: \:\:= \rm\sqrt{100} \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \: \:  \:  \:   \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:\\\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \:\: \rm   \underline{\boxed{\red{ \:  = 10 \: }}} \green✓

\:  \:

\rm \: Therefore, \:  λ =   \cancel{\frac{5}{10} } \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \underline  {  \: \boxed{ \red{\: \rm = 0.5\:}}}{  \green ✓ }

Hope helps ~

\color{purple}\frak{SarcasticSmileeᥫ᭡}

`

4 0
2 years ago
What is the acceleration of an object that moves at constant velocity? What is the net force on the object in this case? What is
Misha Larkins [42]

Answer: What is the acceleration of an object that moves at constant velocity?  Acceleration is Zero

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Fnet= m* a as v is constant a=0 this Fnet is zero.

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