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4 years ago

PLZ HELP

Chemistry

2 answers:

nika2105 [10]4 years ago

8 0

Mjdksksksnsjdkjdjsksksjdndnd

denis23 [38]4 years ago

3 0

I do not believe you can tell the displacement by the information given. so i would say none of the above.

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The proton has a mass of?

aliina [53]

The relative mass is 1

3 0

3 years ago

The prefix 'mili-' means a thousandth. So a mili-liter is a thousandth of a liter. 1 mili-liter = 1/1000 liter How many liters i

Vesnalui [34]

it would be 0.623 hope this helps

3 0

4 years ago

During the discussion of gaseous diffusion for enriching uranium, it was claimed that 235UF6 diffuses 0.4% faster than 238UF6. S

Kay [80]

<u>Answer:</u> The below calculations proves that the rate of diffusion of $^{235}UF_6$ is 0.4 % faster than the rate of diffusion of $^{238}UF_6$

<u>Explanation:</u>

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

We are given:

Molar mass of $^{235}UF_6=349.034348g/mol$

Molar mass of $^{238}UF_6=352.041206g/mol$

By taking their ratio, we get:

$\frac{Rate_{(^{235}UF_6)}}{Rate_{(^{238}UF_6)}}=\sqrt{\frac{M_{(^{238}UF_6)}}{M_{(^{235}UF_6)}}}$

$\frac{Rate_{(^{235}UF_6)}}{Rate_{(^{238}UF_6)}}=\sqrt{\frac{352.041206}{349.034348}}\\\\\frac{Rate_{(^{235}UF_6)}}{Rate_{(^{238}UF_6)}}=\frac{1.00429816}{1}$

From the above relation, it is clear that rate of effusion of $^{235}UF_6$ is faster than $^{238}UF_6$

Difference in the rate of both the gases, $Rate_{(^{235}UF_6)}-Rate_{(^{238}UF_6)}=1.00429816-1=0.00429816$

To calculate the percentage increase in the rate, we use the equation:

$\%\text{ increase}=\frac{\Delta R}{Rate_{(^{235}UF_6)}}\times 100$

Putting values in above equation, we get:

$\%\text{ increase}=\frac{0.00429816}{1.00429816}\times 100\\\\\%\text{ increase}=0.4\%$

The above calculations proves that the rate of diffusion of $^{235}UF_6$ is 0.4 % faster than the rate of diffusion of $^{238}UF_6$

3 0

3 years ago

Identify a process that is NOT reversible. A. melting of steel B. freezing water C. melting of ice D. frying an egg E. depositio

vredina [299]

I’m pretty sure it would be D. Frying an egg

8 0

4 years ago

I need help pls I will give you brainlist

White raven [17]

Answer:

I think it is the second one

Explanation:

Because what the cold water did to the table salt, is that it separated its molecules dissolving the salt.

even though the rock salt was in hot water it was a bigger particle. But the big difference was only because the water temperature ️.

5 0

3 years ago