Answer:
296.01 J
Explanation:
From the question,
Q = cm(t₂-t₁)....................... Equation 1
Where Q = quantity of heat, c = specific heat capacity of aluminium, m = mass of aluminium, t₁ = Initial temperature, t₂ = Final temperature
Given: c = 897 J/kg.K, m = 0.01 kg, t₁ = 22 K, t₂ = 55 k
Substitute these values into equation 1
Q = 897×0.01×(55-22)
Q = 897×0.01×33
Q = 296.01 J
Hence 296.01 Joules of heat is required.
Answer: Option (A) and (D) are the correct statements.
Explanation:
Potential energy is defined as the energy obtained by an object due to its position. Whereas kinetic energy is defined as the energy obtained by an object due to the motion of its molecules.
When there will be only one phase present then addition or removal of energy will lead to change in kinetic energy of the substance but no change in potential energy will take place.
Whereas if change in phase is occurring then adding or removing any energy will lead to change in potential energy of the substance while kinetic energy will remain the same.
Thus, we can conclude that correct statements are as follows.
- While only one phase is present, adding or removing energy changes PE but not KE.
- During a phase change, adding or removing energy changes PE but not KE.
As the radial distance between two objects increases, the gravitational force which pulls the two towards each other decreases following the inverse square law. This is based on Newton's Law of Universal Gravitation, which as an equation states . If the distance between the two is doubled, the force of gravity is only 1/4 as strong. If it is tripled, it is only 1/9 as strong, and so on.
Answer:
1200N
Explanation:
Suppose a body of mass "m" and its weight on the moon is Wm (where W is the weight and "m" is the moon ;which means weight on the moon).Mass of the moon is "M"
and its radius is "R"
Weight of an object on the moon = "F"(Force)with which the moon pulls.
Wm = GM*m/r2
Weight of the same object on the earth is We(where W is the weight and "e" is the earth; which means weight on the earth).
Mass of the earth is 100 times of that of the moon.
Radius of the moon = R
Radius of the Earth = 4R
Weight of the object on the moon =
We = G100M*m/(4R)2(Pronounced 4 R square)
We = G100M*m/(16R)2(Pronounced 16 R square)
Wm/We = G * M * m * 16R2/R2 * g * 100M * m
=16/100
Therefore, 4800N on earth= 1200N on moon