A simple machine has velocity ratio 3, what did you mean
1 answer:
Answer:
A simple machine having a velocity ratio of 3 simply means that the ratio of the distance moved by effort to the distance moved by load is equal to 3.
Explanation:
A simple machine can be defined as a type of machine with no moving parts but can be used to perform work.
Basically, a simple machine allows for the transformation of energy into work. The six simple machines are;
I. Inclined plane.
II. Screw.
III. Wheel and axle.
IV. Lever.
V. Wedge.
VI. Pulley.
Mathematically, the velocity ratio of a simple machine is given by the formula;
Hence, a simple machine having a velocity ratio of 3 simply means that the ratio of the distance moved by effort to the distance moved by load is equal to 3.
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Answer: Below is the complete question
A spherical piece of candy is suspended in flowing water. The candy has a density of 1950 kg/m3 and has a 1.0 cm diameter. The water velocity is 1.0 m/s, the water density is assumed to be 1000.0 kg/m3, and the water viscosity is 1.0x10-3 kg/m/s. The diffusion coefficient of the candy solute in water is 2.0x10-9 m2/s, and the solubility of the candy solute in water is 2.0 kg/m3. Calculate the mass transfer coefficient (m/s)
answer:
mass transfer coefficient = 9.56 * 10^-5 m/s
Explanation:
Candy density = 1950 kg/m^3
Candy diameter = 1 cm
Velocity of water = 1 m/s
water density = 1000 kg/m^3
Viscosity of water = 1 * 10^-3 kg/m/s
diffusion coefficient of candy in water = 2 * 10^-9 m^2/s
solubility of candy = 2 kg/m^3
<u>Determine the mass transfer coefficient ( m/s ) </u>
( Sh) mass transfer coefficient ( flow across sphere ) = 2 + 0.6Re^1/2 * SC^1/3
where : Re = vdp / μ , Sh = KLd / Deff
attached below is the remaining solution .
mass transfer coefficient = 9.56 * 10^-5 m/s
