There are two laws named for Kirchhoff. The both concern electrical circuits.
Here they are in my own words:
1). The sum of the voltage drops around any closed loop in a circuit is zero.
2). The sum of the currents at any single point in a circuit is zero.
To solve this problem we will apply the concept of magnification, which is given as the relationship between the focal length of the eyepieces and the focal length of the objective. This relationship can be expressed mathematically as,
Here,
= Magnification
= Focal length eyepieces
= Focal length of the Objective
Rearranging to find the focal length of the objective
Replacing with our values
Therefore the focal length of th eobjective lenses is 27.75cm
For a wave is described by y=0.0200 sin (kx - ωt) , where , ω = 3.62 rad/s, x and y are in meters, and t is in seconds, the wavelength = 2.978
<h3>How to solve for the wavelength</h3>
What is wave speed?
This is used to refer to the speed at which a wave is moving. It is the product of frequency and wave number
Given data
y=0.0200 sin (kx - ωt)
ω = 3.62 rad/s
y are in meters
t is in seconds
k = 2.11 rad/m
k = wavenumber = 2 * pi / wavelength
wavelength = 2 * pi / wavenumber
wavelength = 2 * pi / 2.11
wavelength = 2.978
Read more on wavelength here
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Answer:
The correct solution is "14.6875 kg".
Explanation:
Given values:
Force,
F = 47.0 N
Acceleration,
a = 3.20 m/s²
Now,
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or,
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Answer: cleft grafting, inlay grafting, four-flap grafting, and whip grafting.
Explanation:
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