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kobusy [5.1K]
2 years ago
8

Determine the number of moles of C in each sample

Chemistry
1 answer:
stepan [7]2 years ago
7 0

<u>Explanation:</u>

  • <u>In </u>CH_4<u>:</u>

Given moles = 2.0 moles

1 mole of methane contains 1 mole of carbon and 4 moles of hydrogen

Moles of carbon in CH_4=(2.0\times 1)=2.0 moles

  • <u>In </u>C_2H_6<u>:</u>

Given moles = 0.175 moles

1 mole of ethane contains 2 moles of carbon and 6 moles of hydrogen

Moles of carbon in C_2H_6=(0.175\times 2)=0.35 moles

  • <u>In </u>C_4H_{10}<u>:</u>

Given moles = 4.21 moles

1 mole of butane contains 4 moles of carbon and 10 moles of hydrogen

Moles of carbon in C_4H_{10}=(4.21\times 4)=16.84 moles

  • <u>In </u>C_8H_{18}<u>:</u>

Given moles = 24.5 moles

1 mole of octane contains 8 moles of carbon and 18 moles of hydrogen

Moles of carbon in C_8H_{18}=(24.5\times 8)=196 moles

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Mg(OH)2 + 2HNO3 → Mg(NO3)2 + 2H20
LenaWriter [7]

Answer:

A. 1350

You multiply 18.21HNO3* 1mol MgN2O6 * 148.30MgN2O6

Then divide it by the 2mol HNO3 to get 1350

3 0
3 years ago
5. How many moles of gas are in a 7.5 L container, at 1 atm of pressure, at 100 degrees
loris [4]

Answer:

Ok; just use PV=nRT solve for n.

Explanation:

7 0
3 years ago
Glucose, C6H12O6,C6H12O6, is used as an energy source by the human body. The overall reaction in the body is described by the eq
Ilia_Sergeevich [38]

Answer:

Mass of oxygen = 61.824 g

Mass of carbon dioxide = 85.01 g

Explanation:

Given data:

Mass of glucose = 58 g

Mass of carbon dioxide = ?

Mass of oxygen = ?

Solution:

First of all we will write the balanced chemical equation,

C₆H₁₂O₆  + 6O₂       →    6CO₂  + 6H₂O

Moles of glucose:

Number of moles = mass / molar mass

Number of moles = 58 g/180 g/mol

Number of moles =  0.322 mol

Now we compare the moles of oxygen with glucose from balance chemical equation.

                             C₆H₁₂O₆          :              O₂  

                                    1                :              6

                                    0.322       :              0.322×6 = 1.932 mol

Mass of oxygen:

Mass of oxygen = number of moles × molar mass

Mass of oxygen =  1.932 mol × 32 g/mol

Mass of oxygen =  61.824 g

Now we compare the moles of carbon dioxide with moles of glucose and oxygen.

                              C₆H₁₂O₆            :              CO₂

                                   1                   :                 6

                                  0.322           :           0.322×6 = 1.932 mol

                                   

                                 O₂                    :                 CO₂

                                  6                     :                  6

                                 1.932                :                  1.932

Mass of carbon dioxide;

mass of carbon dioxide = number of moles × molar mass

mass of carbon dioxide =  1.932 mol × 44 g/mol

mass of carbon dioxide =  85.01 g

7 0
3 years ago
A sample of Neon is in a sealed container held under isothermic conditions. The initial pressure and volume are 2.7 atm and 4.5
Marina CMI [18]

Answer:

The final volume in mL is 7.14 mL or 7.1 mL.

Explanation:

1.Use Boyle's Law(P_{1} V_{1}= P_{2} V_{2}). Re-arrange to solve for V_{2}<em> for the final volume.</em>

<em />

<em>2. Plug in values. </em>V_{2} =\frac{(2.7 atm)(4.5 mL)}{(1.7 atm)}  = 7.14 mL

3 0
2 years ago
Examples<br> 1) How many atoms of silver are there in 4.5 moles of silver? [Ag = 107.8682 g/mol]
Anon25 [30]
3.0x10-4..............................
7 0
3 years ago
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