Answer:
V₂ = 0.74 L
Explanation:
Given data:
Initial volume of balloon = 0.75 L
Initial temperature of balloon = 27°C (27+273.15 K = 300.15 K)
Final volume of balloon = ?
Final temperature = 22°C (22+273.15 K = 295.15 k)
Solution:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 0.75 L × 295.15 k / 300.15 K
V₂ = 221.36 L.K / 300.15 K
V₂ = 0.74 L
The given problem is solved through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
True
False
False
True
I think so
Answer:
Its Neutral
Explanation:
I got this right in a quiz. I hope this helps!!
Answer:
This question is asking to find the new temperature
The answer for the final temperature is 429.73K
Explanation:
Using Charles law equation as follows:
V1/T1 = V2/T2
Where;
V1 = initial volume (L)
V2 = final volume (L)
T1 = initial temperature (K)
T2 = final temperature (K)
According to this question;
V1 = 3.0L
V2 = 4.4L
T1 = 20°C = 20 +273 = 293K
T2 = ?
Using V1/T1 = V2/T2
3/293 = 4.4/T2
Cross multiply
293 × 4.4 = 3 × T2
1289.2 = 3T2
T2 = 1289.2 ÷ 3
T2 = 429.73K
