Answer:
Y = 176.4 m
Explanation:
For the height of cliff we will analyze the vertical motion. We will apply the 2nd equation of motion:
Y = V₀y*t + (0.5)gt²
where,
Y = Height = ?
V₀y = Initial Vertical Velocity = 0 m/s (since, ball is thrown horizontally)
t = time = 6 s
g = 9.8 m/s²
Therefore,
Y = (0 m/s)(6 s) + (0.5)(9.8 m/s²)(6 s)²
<u>Y = 176.4 m</u>
Hand grip test an example of an isometric muscle contraction.
Isometric(increased pressure but no shortening)
Explanation:
- Isometric contraction, is one in which the muscle is activated, but instead of being allowed to lengthen or shorten, it is held at a constant length.
- An isometric exercise is a form of exercise involving the static contraction of a muscle without any visible movement in the angle of the joint.
- Isometric exercises are contractions of a particular muscle or group of muscles. During isometric exercises, the muscle doesn't noticeably change length and the affected joint doesn't move. Isometric exercises help maintain strength. They can also build strength, but not effectively.
- Isometric exercise is also known as static strength training. (Examples include the plank and side bridge as well as the wall sit and many yoga poses such as chair and tree poses).
Answer:
Explanation:
- The volume of water displaced by immersing the object is equal the amount of water spilled and caught by Dr. Hewitt.
- The amount of water is proportional to the volume of object of fraction of object immersed in water will lead to the same fraction of water displaced and caught by Dr. Hewitt.
- When the object is immersed the force of Buoyancy acts against the weight and reducing the scale weight.
- The amount of Buoyancy Force is proportional to the fraction of Volume of object immersed in water; hence, the same amount is spilled/lost.
Partial. a penumbral lunar eclipse is when the moon passes through the earths penumbra
Answer:
Ek = 1705.28 [J]
Explanation:
In order to solve this problem, we must remember that kinetic energy can be calculated by means of the following equation.
where:
m = mass [kg]
v = velocity [m/s]
Ek = kinetic energy [J] (Units of Joules)
<u>For the person running</u>
<u />![E_{k} =\frac{1}{2}*52.2*(3.5)^{2} \\ E_{k} =319.72[J]](https://tex.z-dn.net/?f=E_%7Bk%7D%20%3D%5Cfrac%7B1%7D%7B2%7D%2A52.2%2A%283.5%29%5E%7B2%7D%20%5C%5C%20E_%7Bk%7D%20%3D319.72%5BJ%5D)
<u />
<u />
<u>For the bullet</u>
<u />
<u />
<u />![E_{k} =\frac{1}{2} *0.02*(450)^{2} \\E_{k}=2025 [J]](https://tex.z-dn.net/?f=E_%7Bk%7D%20%3D%5Cfrac%7B1%7D%7B2%7D%20%2A0.02%2A%28450%29%5E%7B2%7D%20%5C%5CE_%7Bk%7D%3D2025%20%5BJ%5D)
<u />
<u />
The difference in Kinetic energy is equal to:
Ek = 2025 - 319.72
Ek = 1705.28 [J]
