A car is traveling at 13 m/s and accelerates at - 0.95

Physics

1 answer:

riadik2000 [5.3K]3 years ago

3 0

Answer:

v = 12.3 m / s

Explanation:

This is an exercise in kinetics in one dimension

v² = v₀² + 2 a x

In this exercise they tell us that the initial velocity is (v₀ = 13 m / s), the acceleration is a = -0.95 m / s2 and the distance x = 9.2 m

we substitute

v = √ (13 2 - 2 0.95 9.2)

v = 12.3 m / s

note that as the acceleration is negative the vehicle is stopping

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Answer:

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A 0.03 kg golf ball is hit off the tee at a speed of 34 m/s. The golf club was in contact with the ball for 0.003 s. What is the

Liula [17]

Answer:

The average force on ball by the golf club is 340 N.

Explanation:

Given that,

Mass of the golf ball, m = 0.03 kg

Initial speed of the ball, u = 0

Final speed of the ball, v = 34 m/s

Time of contact, $\Delta t=0.003\ s$

We need to find the average force on ball by the golf club. We know that the rate of change of momentum is equal to the net external force applied such that :

$F=\dfrac{\Delta p}{\Delta t}\\\\F=\dfrac{mv-mu}{\Delta t}\\\\F=\dfrac{mv}{\Delta t}\\\\F=\dfrac{0.03\ kg\times 34\ m/s}{0.003\ s}\\\\F=340\ N$