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Aleksandr-060686 [28]

3 years ago

10

Does anyone know the answer to this? 40y^3-8y^2+16y/8y^2

1 answer:

soldi70 [24.7K]3 years ago

4 0

Simplify: 40y^3 - 8y^2 + 16y/8 y^2
40y^3 + -8y^2 + 2y^3

Combine terms: 40y^3 + -8y^2 + 2y^3
(40y^3 + 2y^3) + (-8y^2)

Answer: 42y^3 + -8y^2

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ludmilkaskok [199]

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Step-by-step explanation:

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garri49 [273]

Answer:

The area of the regular hexagon is $166.3\ units^{2}$

Step-by-step explanation:

we know that

The area of a regular hexagon can be divided into 6 equilateral triangles

so

step 1

Find the area of one equilateral triangle

$A=\frac{1}{2}(b)(h)$

we have

$b=r=8\ units$

$h=4\sqrt{3}\ units$ ----> is the apothem

substitute

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step 2

Find the area of 6 equilateral triangles

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7 0

2 years ago