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allsm [11]
3 years ago
7

What is the formula for calculating the efficiency of a heat engine? Efficiency = StartFraction T Subscript h Baseline minus T S

ubscript C Baseline over T Subscript h Baseline EndFraction times 100. Efficiency equals T Subscript c Baseline minus T Subscript h Baseline over T Subscript h Baseline all times 100. Efficiency equals T Subscript h Baseline minus T Subscript c Baseline over T Subscript c Baseline all times 100. Efficiency equals T Subscript c Baseline minus T Subscript h Baseline over T Subscript c Baseline all times 100.
Physics
1 answer:
Anna007 [38]3 years ago
9 0

Efficiency of heat engine is determined by the ratio of difference in temperature of cold from hot reservoir to the temperature of hot reservoir over temperature of hot reservoir.

Answer: Option A

<u>Explanation:</u>

Efficiency is defined as the output from the input. So it is the ratio of energy output to the energy input. In case of temperature, it is the change in temperature from hot reservoir to cold reservoir with the overall hot reservoir temperature.

Efficiency =\frac{T_{h} -T_{c} }{T_{h} }

Thus, option A is the most suitable as the heat will be transferred from high temperature to low temperature. So the hot reservoir will be releasing the energy. So the conversion of hot reservoir temperature to cool reservoir temperature is defined as the efficiency. Thus, option A is the most suitable.

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gogolik [260]

Answer:

(a) 1 : 2

(b) same

Explanation:

Let the mass of puck A is m and the mass of puck B is 2 m.

initial speed for both the pucks is same as u and the distance is same for both is s.

let the tension is T for same.

The kinetic energy is given by

K = 0.5 mv^2

(a) As the speed is same, so the kinetic energy depends on the mass.

So, kinetic energy of A : Kinetic energy of B = m : 2m  = 1 : 2

(b) A the distance s same so the final velocities are also same.

8 0
2 years ago
B) A satellite with mass m orbits the Earth at a radius r. A second satellite also with mass m orbits the
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Answer:

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6 0
3 years ago
Find the length of a pendulum that oscillates with a frequency of 0.16 hz. the acceleration due to gravity is 9.81 m/s 2 . answe
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The period of the pendulum is the reciprocal of the frequency:
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T=2 \pi  \frac{L}{g}
where L is the length of the pendulum, and g the acceleration of gravity. By re-arranging the formula and using the value of T we found before, we can  calculate the length of the pendulum L:
L=g  \frac{T^2}{(2 \pi)^2}=(9.81 m/s^2)  \frac{(6.25 s)^2}{(2 \pi)^2}=9.71 m
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3 years ago
How much energy is required to move an electron through a potential difference of
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2 years ago
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attashe74 [19]

Answer:

b

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I think im not really sure tho

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