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bazaltina [42]
3 years ago
11

If you drop a 200 gram piece of metal with a temperature of 110 degrees Celsius into 1000 grams of water at 25° Celsius, what be

st describes what would occur?
The water will quickly reach the boiling point.

The water's temperature will stay the same, but the metal will cool down.

The water's temperature will increase, and the temperature of the metal will stay constant.

The water and the metal's temperatures will reach the same temperature.
Physics
1 answer:
Vlad1618 [11]3 years ago
7 0
<span>Usually, If you drop a 200 gram piece of metal with a temperature of 110 degrees Celsius into 1000 grams of water at 25° Celsius, the statement which would best describe what would occur is the last one : </span><span>The water and the metal's temperatures will reach the same temperature. I choose this one because this is a nice example of how the nature tries to reach the balance. Hope it helps! Regards.</span>
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Write down the principal of lever​
pashok25 [27]

Answer:

See the explanation below.

Explanation:

A lever is a simple machine that changes the magnitude and direction of the force applied to move an object. Minimizes the force needed to lift the object.

By means of the following image, we can see the principle of operation of a lever.

The load can be moved thanks to the force multiplied by the distance to the fulcrum.

3 0
3 years ago
A truck heading east has an initial velocity of 6/ms. It accelerates at 2/ms2 for 12 seconds. What distance does the truck trave
frez [133]

Answer:

216m

Explanation:

As we know S=ut+1/2at^2

S=6×12+1/2×2×12×12

=72+144

=216 m

4 0
3 years ago
A 3.1 kg ball is dropped from the top of a 38 m tall building. What is the speed of the ball when it is halfway from the buildin
Archy [21]

Answer:

19.3m/s

Explanation:

Use third equation of motion

v^2-u^2=2gh

where v is the velocity at halfway, u is the initial velocity, g is gravity (9.81m/s^2) and h is the height at which you'd want to find the velocity

insert values to get answer

v^2-0^2=2(9.81m/s^2)(38/2)\\v^2=9.81m/s^2 *38\\v^2=372.78\\v=\sqrt[]{372.78} \\v=19.3m/s

4 0
3 years ago
*please refer to photo* An electric field of magnitude 5.25 ✕ 10^5N/C points due south at a certain location. Find the magnitude
kvv77 [185]

Answer:

Approximately 3.86\; {\rm N} (given that the magnitude of this charge is -7.35\; {\rm \mu C}.)

Explanation:

If a charge of magnitude q is placed in an electric field of magnitude E, the magnitude of the electrostatic force on that charge would be F = E\, q.

The magnitude of this charge is q = 7.35\; {\rm \mu C}. Apply the unit conversion 1\; {\rm \mu C} = 10^{-6}\; {\rm C}:

\begin{aligned} q &= 7.35\; {\mu C} \times \frac{10^{-6}\; {\rm C}}{1\; {\mu C}} = 7.35\times 10^{-6}\; {\rm C}\end{aligned}.

An electric field of magnitude E = 5.25\times 10^{5}\; {\rm N \cdot C^{-1}} would exert on this charge a force with a magnitude of:

\begin{aligned}F &= E\, q \\ &= 5.25 \times 10^{5}\; {\rm N \cdot C^{-1}} \times (-7.35\times 10^{-6}\; {\rm C}) \\ &\approx 3.86\; {\rm N}\end{aligned}.

Note that the electric charge in this question is negative. Hence, electrostatic force on this charge would be opposite in direction to the the electric field. Since the electric field points due south, the electrostatic force on this charge would point due north.

4 0
2 years ago
what happens to the gravitational force when the distance between them stays the same and the mass of both objects is doubled
Dimas [21]

Answer:

The strength of the gravitational force between two objects depends on two factors, mass and distance. the force of gravity the masses exert on each other. If one of the masses is doubled, the force of gravity between the objects is doubled. increases, the force of gravity decreases.

Explanation:

7 0
3 years ago
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