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bazaltina [42]
3 years ago
11

If you drop a 200 gram piece of metal with a temperature of 110 degrees Celsius into 1000 grams of water at 25° Celsius, what be

st describes what would occur?
The water will quickly reach the boiling point.

The water's temperature will stay the same, but the metal will cool down.

The water's temperature will increase, and the temperature of the metal will stay constant.

The water and the metal's temperatures will reach the same temperature.
Physics
1 answer:
Vlad1618 [11]3 years ago
7 0
<span>Usually, If you drop a 200 gram piece of metal with a temperature of 110 degrees Celsius into 1000 grams of water at 25° Celsius, the statement which would best describe what would occur is the last one : </span><span>The water and the metal's temperatures will reach the same temperature. I choose this one because this is a nice example of how the nature tries to reach the balance. Hope it helps! Regards.</span>
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Answer:

When the ball hits the ground, the velocity will be -34 m/s.

Explanation:

The height and velocity of the ball at any time can be calculated using the following equations:

y = y0 + v0 · t + 1/2 · g · t²

v = v0 + g · t

Where:

y = height of the ball at time "t".

y0 = initial height.

v0 = initial velocity.

t = time.

g = acceleration due to gravity. (-9.8 m/s² considering the upward direction as positive).

v = velocity at time "t".

If we place the origin of the frame of reference on the ground, when the ball hits the ground its height will be 0. Then using the equation of height, we can calculate the time it takes the ball to reach the ground:

y = y0 + v0 · t + 1/2 · g · t²

0 = 60 m + 0 m/s · t - 1/2 · 9.8 m/s² · t²

0 = 60 m - 4.9 m/s² · t²

-60 m / -4.9 m/s² = t²

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Now, with this time, we can calculate the velocity of the ball when it reaches the ground:

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Subcultures build up their own standards and qualities with respect to social, political and sexual issues

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The momentum change of the system during the collision is always equals to one another.

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