Heat supplied to the gold will raise the temperature of the gold from 20 degree Celsius to 90 degree Celsius.
Mass of the gold (m) = 0.072 kg
Temperature change (ΔT) = 90 - 20 = 70 degree Celsius
Specific heat capacity of the gold (c) = 136 J/kg C
Heat supplied = m × c × ΔT
Heat supplied = 0.072 × 136 × 70
Heat supplied = 685.44 Joules
Hence, the heat supplied to the gold to raise the temperature from 20 degree Celsius to 90 degree Celsius = 685.44 Joules
Answer:
Perfectly inelastic collision
Explanation:
There are two types of collision.
1. Elastic collision : When the momentum of the system and the kinetic energy of the system is conserved, the collision is said to be elastic. For example, the collision of two atoms or molecules are considered to be elastic collision.
2. Inelastic collision: When the momentum the system is conserved but the kinetic energy is not conserved, the collision is said to be inelastic. For example, collision of a ball with the mud.
For a perfectly elastic collision, the two bodies stick together after collision.
Here, the meteorite collide with the Mars and buried inside it, the collision is said to be perfectly inelastic. here the kinetic energy of a body lost completely during the collision.
Action and reaction are the rocket fuel going backwards and the rocket going forward. 3
f=ma 2
the rocket was at rest, 1, until there was a resultant external force 1 at which point 2 came in, with 3 alongside
Answer:
1.) Putting club or the putter
2.) Either the 4-, 5-, or the 6- iron club
3.) 14 clubs
4.) The height of the golfer
Explanation:
I used to golf
Answer:
The direction of the momentum of the large ball after the collision with respect to east is 146.58°.
Explanation:
Given that,
Mass of large ball = 3.0 kg
Mass of steel ball = 1.0 kg
Velocity = 3.0 kg
After collision,
Velocity = 2.0 m/s
Using conservation of momentum
The direction of the momentum
The direction of the momentum with respect to east
Hence, The direction of the momentum of the large ball after the collision with respect to east is 146.58°.
