A. Metal
B. Metalloid
C. Nonmetal
D. Metal
The question requires to balance the equation.
The equation is already balanced, so the answer is:
<span>Ca(s)+Br2(l)⟶CaBr2(s)
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</span><span>Explanation:
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</span><span>1) The phases are identified with a letter to the right of the compound or element:
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</span><span>So, for Ca, the phase is (s) which means solid.
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</span><span>For Br₂ (l) the phase is (l) which means liquid.
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</span><span>For CaBr₂(s) the phase is (s) which means solid.
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</span><span>2) The core work of balancing is make the number of atoms of each element on the reactants equal to the same number of atoms on the products side.
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</span><span>That is the law of conservation of mass applied to chemcial reactions.
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</span><span>3) So, you have to add coefficientes on the right place to make the number of atoms on the left side equal to the number of the same kind of atom on the right side.
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</span><span>In this table you can verify that the equation given is balanced:
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</span><span>atom left side right side
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</span><span>Ca 1 1
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</span><span>Br 2 2
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</span><span>So, you do not need to modify any coefficients.
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Answer:
The given equation is not balanced.
Explanation:
Chemical equation:
3H₂ + 3Cl₂ → HCl
The balanced equation always have equal number of atoms on both side of equation. In this equation on left side there are six atoms of chlorine and six atoms of hydrogen are present while on right side only one atom of hydrogen and one atom of chlorine are present.
The balanced equation always follow the law of conservation of mass.
According to the law of conservation of mass, mass can neither be created nor be destroyed in a chemical reaction.
It means reactant and product always have same mass.
The given equation can written as balanced equation as follows,
Balanced chemical equation:
3H₂ + 3Cl₂ → 6HCl
There are equal number of atoms of hydrogen and chlorine are present on both side of equation so it follow the law of conservation of mass.
Answer:
VSEPR PRINCIPLE
Explanation:
I did some research and that was what I found, I hope this helps.
I wanna say it would be 1 would be A 2 would be C 3 would be D 4 would be B and 5 would be E
hope this helps
