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Arada [10]
3 years ago
11

PLEASE HELP ASAP!!!!!!

Chemistry
1 answer:
jeka57 [31]3 years ago
3 0

<u>Answer:</u>

The correct answer option is 'gravity acting on the edges of plates and convection in the mantle'.

<u>Explanation:</u>

The two processes which the scientists think that move the Earth's lithosphere plates are:

1) gravity acting on the edges of the plates; and

2) convection in the mantle

The gravitational body force pulling the slab downwards is balanced by the resistive forces acting on the plate while mantle convection is the main way through which the heat from Earth's interior is transferred to its surface.

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What are some examples of van der waals forces?
Rudiy27

It's examples are:

1)London dispersion forces

2)Dipole-Dipole forces

3)Hydrogen bonding...

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3 years ago
Which of the following instruments has the highest pitch?<br> bass drum<br> flute<br> trombone
sweet [91]

Answer:

Flute

Explanation:

7 0
2 years ago
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What is the molarity of a solution that contains 122g of MgSO4 n 3.5L of solution?​
Semmy [17]

Answer:

0.29mol/L or 0.29moldm⁻³

Explanation:

Given parameters:

Mass of MgSO₄ = 122g

Volume of solution = 3.5L

Molarity is simply the concentration of substances in a solution.

Molarity = number of moles/ Volume

>>>>To calculate the Molarity of MgSO₄ we find the number of moles using the mass of MgSO₄ given.

Number of moles = mass/ molar mass

Molar mass of MgSO₄:

Atomic masses: Mg = 24g

S = 32g

O = 16g

Molar mass of MgSO₄ = [24 + 32 + (16x4)]g/mol

= (24 + 32 + 64)g/mol

= 120g/mol

Number of moles = 122/120 = 1.02mol

>>>> From the given number of moles we can evaluate the Molarity using this equation:

Molarity = number of moles/ Volume

Molarity of MgSO₄ = 1.02mol/3.5L

= 0.29mol/L

IL = 1dm³

The Molarity of MgSO₄ = 0.29moldm⁻³

8 0
3 years ago
Balance the following reaction. As2S3 + 9O2 → 2As2O3 + SO2
kumpel [21]

Answer:

2As2S3 + 9O2 = 2As2O3 + 6SO2

Explanation:

8 0
3 years ago
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When carbon is burned in air, it reacts with oxygen to form carbon dioxide. When 14.4 g of carbon were burned in the presence of
Yanka [14]

Answer:

Mass of carbon dioxide produced = 52.8 g

Explanation:

Given data:

Mass of carbon react = 14.4 g

Mass of oxygen = 56.5 g

Mass of oxygen left = 18.1 g

Mass of carbon dioxide produced = ?

Solution:

C + O₂     →      CO₂

Number of moles of C:

Number of moles = mass/ molar mass

Number of moles = 14.4 g/ 12 g/mol

Number of moles = 1.2 mol

18.1 g of oxygen left it means carbon is limiting reactant.

Now we will compare the moles of C with CO₂.

                       C             :         CO₂

                        1             :          1

                      1.2           :          1.2

Mass of CO₂:

Mass = number of moles × molar mass

Mass = 1.2  mol × 44 g/mol

Mass = 52.8 g

8 0
2 years ago
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