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3 years ago

Complete the following sentence. In a fluid, pressure __________ with depth. increasesdecreasesdoesn't change

1 answer:

4 0

Increase Complete the following sentence. In a fluid, pressure increase with depth regardless of the shape of the container.

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A sample of gas at 15 atmospheres and 445 K is cooled to 250 K. What pressure will the gas be under after it is cooled? Round to

faltersainse [42]

Answer:

Explanation: 8.43

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3 years ago

A pump contains 1.5 L of air at 175 kPa. You draw back on the piston of the pump, expanding the volume until the pressure reads

Tresset [83]

Answer:

$\large \boxed{\text{86.8 L}}$

Explanation:

The temperature and amount of gas are constant, so we can use Boyle’s Law.

$p_{1}V_{1} = p_{2}V_{2}$

Data:

$\begin{array}{rclrcl}p_{1}& =& \text{0.579 atm}\qquad & V_{1} &= & \text{150 L} \\p_{2}& =& \text{1.00 atm}\qquad & V_{2} &= & ?\\\end{array}$

Calculations:

$\begin{array}{rcl}0.579 \times 150 & =& 1.00V_{2}\\86.85 & = & 1.00V_{2}\\V_{2} & = &\dfrac{86.85}{1.00}\\\\& = &\textbf{86.8}\\\end{array}\\\text{The new volume of the gas is } \large \boxed{\textbf{86.8 L}}$

6 0

3 years ago

Why does H2O have a lower melting point than MgO

Vesnalui [34]

Answer:

Magnesium Oxide (MgO) has a higher melting point than Sodium Chloride (NaCl) which is around 2,800 degrees Celcius. This is because its Mg2+ and O2- ions have a greater number of charges, and so form stronger ionic bonds, than the Na+ and Cl– ions in Sodium Chloride.

4 0

3 years ago

Hydrogen bond is an example for? (PLEASE HELP!)

zlopas [31]

Answer:

Explanation:

hydrogen bond is a form of dipole-dipole interaction but with more unique properties

3 0

3 years ago

PLEASE HELP!!!

neonofarm [45]

Answer:

$Cl_2+2NaI\rightarrow I_2+2NaCl$

Explanation:

Hello there!

In this case, according to the described chemical reaction, Cl2 replaces iodine in NaI in order to produce I2 and NaCl:

$Cl_2+NaI\rightarrow I_2+NaCl$

It is possible to realize how chlorine replaces iodine in agreement with the single displacement reaction. Moreover, since chlorine and iodine atoms are not correctly balanced, we add a 2 in front of both NaI and NaCl in order to do so:

$Cl_2+2NaI\rightarrow I_2+2NaCl$

Best regards!

8 0

3 years ago