#5
5(p+6)=8p
5p+30=8p
8p-5p=30
3p=30
30/3
p= 10 is your answer
#4
3(g+7)=2(10+g)
3g-21=20+2g
3g-2g
g-21=20
20+21
g=41 is your answer
#6
3/7 w -11= -4/7 w
3/7w=-4/7 + 11
3/7 w = 73/7 x 7
3w = 511/7
3w= 73
w= 73/7 is your answer
24 times 3= 72+4=76+14=90
^
Answer:
57.93% probability that a trip will take at least 35 minutes.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a trip will take at least 35 minutes
This probability is 1 subtracted by the pvalue of Z when X = 35. So



has a pvalue of 0.4207
1 - 0.4207 = 0.5793
57.93% probability that a trip will take at least 35 minutes.
$20.00 - $15.24 = $4.76 in change. I'd say review decimal subtraction which you should have learned in fourth or fifth grade. Hope this helps!