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beks73 [17]
2 years ago
8

The atomic mass of hydrogen is approximately 1.0079 amu. The atomic mass of an oxygen atom is approximately 15.9994 amu. What is

the molecular mass of water? A.)34.02 amu B.)18.02 amu C.)17.02 amu D.)36.02 amu
Chemistry
1 answer:
inysia [295]2 years ago
3 0

Answer:

\huge\boxed{\sf 18.02 \ amu}

Explanation:

<u>Molecular mass of water:</u>

= H₂O

= 2(Atomic mass of H) + (Atomic mass of O)

= 2(1.0079) + 15.9994

= 2.0158 + 15.9994

= 18.02 amu

\rule[225]{225}{2}

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Explanation:

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3 years ago
Briefly discuss interpretations of your observations and results. Include in your discussion, any conclusions drawn from the res
VMariaS [17]

Answer:

In comparison to Part 1 of this experiment, we observed similar reactions when determining the make up of our unknown. When testing for Mn2+ we observed a color change that resulted in a darker brown/red color, when testing for Co2+ we observed the formation of foamy bubbles but we could not conclude that a gas had formed, when testing for Fe3+ the result was a liquid red in color, when testing for Cr3+ we observed no change, when testing for Zn2+ we observed the formation of a pink/red liquid, when testing for K+ we observed the formation of a precipitate, when testing for Ca2+ we observe the formation of a precipitate. Sources of error may have occurred when observing whether or not an actual reaction had taken place or not, using glassware that wasn't fully cleaned, or the accidental mix of various other liquids in the lab

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3 years ago
Instead of using ratios for back titrations we can also use molarities, if our solutions are standardized. A 0.196 g sample of a
kvv77 [185]

Answer:

The mass percent of Al(OH)₃ is 15.3%

Explanation:

The reaction is:

Al(OH)₃ + 3HCl = AlCl₃ + 3H₂O

The excess acid is neutralized with a solution of sodium hidroxide, in the reaction:

NaOH + HCl = NaCl + H₂O

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n_{HCl,total} =M_{HCl} *V_{HCl} =0.111*0.025=2.78x10^{-3} moles

From the second titration, the moles of excess of HCl is:

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The difference between the total and excess of HCl, it can be know the moles that reacts with the aluminum hydroxide, is:

n_{HCl,reacts} =n_{HCl,total}-n_{HCl,excess} =2.78x10^{-3} moles-1.46x10^{-3} moles=1.32x10^{-3} moles

The ratio between HCl and Al(OH)₃ is 3:1. The MW for aluminum hydroxide is 78 g/mol, thus:

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The percentage of Al(OH)₃ is:

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3 0
3 years ago
What substance is reduced in the reaction 2Fe2+ + Cl2 → 2Fe3+ + 2Cl−?
Vladimir [108]

Answer:

Cl2, because it gained electrons

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7 0
3 years ago
A 75.0 mL 75.0 mL aliquot of a 1.70 M 1.70 M solution is diluted to a total volume of 278 mL. 278 mL. A 139 mL 139 mL portion of
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<em>A 75.0 mL aliquot of a 1.70 M solution is diluted to a total volume of 278 mL.</em>

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C₂ = 0.210 M

7 0
3 years ago
Read 2 more answers
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