The person must stand at a radius of 0.99 m
Explanation:
In order for the person to stand on the merry go round, the force of friction acting on the person must provide the centripetal force necessary to keep the person in uniform circular motion.
Therefore, we can write:
where:
- the term on the left is the force of friction, and the term on the right is the centripetal force
is the coefficient of friction
m is the mass of the person
is the acceleration of gravity
is the angular velocity
r is the radius of the circular path
Solving the equation for r, we find the radius at which the person must be standing:
Learn more about circular motion:
brainly.com/question/2562955
brainly.com/question/6372960
#LearnwithBrainly
Answer:
H=1020.12m
Explanation:
From a balance of energy:
where H is the height it reached, d is the distance it traveled along the ramp and Ff = μk*N.
The relation between H and d is given by:
H = d*sin(30) Replace this into our previous equation:
From a sum of forces:
N -mg*cos(30) = 0 => N = mg*cos(30) Replacing this:
Now we can solve for d:
d = 2040.23m
Thus H = 1020.12m
Answer:
6840 N
Explanation:
The force acting on the car can be found by using Newton's second law:
F = ma
where
F is the net force on the car
m is the mass of the car
a is its acceleration
For the car in this problem,
m = 1800 kg
Substituting,
Answer:
F = 1.69 N
Explanation:
Given that,
Electric field, E = 234,000 N/C
Charge, Q = -7.25 µC
We need to find the electric force acting on the charge. It can be given as follows :
As the charge is negative, the force will act in the opposite direction of electric field. Hence, the electric force is 1.69 N.
