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2 years ago

9

A 1200 kg car traveling at 20.83 m/s comes to a screeching halt in a time of 6.00 seconds. Calculate the force of friction exper

ienced by the car.

1 answer:

Setler [38]2 years ago

4 0

Answer:

4166 N

Explanation:

F x T = 1200 x 20.83

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A person carries a plank of wood 2.00 m long with one hand pushing down on it at one end with a force f1 and the other hand hold

slega [8]

Answer:

F₁ = 4,120.2 N

F₂ = 3,924N

Explanation:

1) Balance of angular momentum around the end where F₁ is applied.

F₂ × 0.5m - F₁ × 0 = mass × g × 1m

⇒ F2 × 0.5 m= 20 kg × 9.81 m/s² × 1 m = 1,962 N×m

F₂ = 196.2 Nm / 0.5m = 3,924 N

2) Balance of forces

F₁ - F₂ = mg

F₁ = F₂ + mg = 3,924N + 20kg (9.81 m/s²) = 4,120.2 N

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3 years ago

If an object starting from rest falls 5.7 seconds how far does it fall

White raven [17]

Kinematic question!
Start with your knowns!

$t = 5.7s \\ v0 = 0 \frac{m}{s} \\ a = - 9.8 \frac{m}{ {s}^{2} }$
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the only kineamtic that works with this info is the third!
$x = v0 \times t + \frac{1}{2} \times a \times {t}^{2}$
so we plug in our values and get
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