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2 years ago

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A 1200 kg car traveling at 20.83 m/s comes to a screeching halt in a time of 6.00 seconds. Calculate the force of friction exper

ienced by the car.

1 answer:

Setler [38]2 years ago

4 0

Answer:

4166 N

Explanation:

F x T = 1200 x 20.83

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In the hydrogen atom, what is the total energy of an electron that is in an orbit that has a radius of 8.784 × 10^(-10) m?

finlep [7]

Answer:

The total energy of an electron in H atom is $1.31\times10^{-19}\ J$ .

Explanation:

Given that,

Radius $R=8.784\times10^{-10}\ m$

We need to calculate the orbit number

Using formula of radius

$R=a_{0}n^2$

$n^2=\dfrac{R}{a_{0}}$

Where, a₀ = boar radius

n = orbit number

Put the value into the formula

$n^2=\dfrac{8.784\times10^{-10}}{0.529\times10^{-10}}$

$n=\sqrt{\dfrac{8.784\times10^{-10}}{0.529\times10^{-10}}}$

$n=4.07$

We need to calculate the total energy of an electron in H atom

Using formula of energy

$E=-\dfrac{13.6}{n^2}$

Put the value into the formula

$E=\dfrac{-13.6}{16.60}\ ev$

$E=0.8192\times1.6\times10^{-19}$

$E=1.31\times10^{-19}\ J$

Hence, The total energy of an electron in H atom is $1.31\times10^{-19}\ J$ .

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3 years ago

Q. Why do molecules of an object moving faster when dropped to the ground?

bija089 [108]

Answer:

the cause of variation gravity

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3 years ago

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What amount of force is needed to propel and object of 27 kg to an acceleration of 11,550 m/s^2?

madreJ [45]

Answer:

311,850 N

Explanation:

We can solve the problem by using Newton's second law:

$F=ma$

where

F is the net force exerted on the object

m is the mass of the object

a is the acceleration

In this problem, we have

m = 27 kg is the mass

a = 11,550 m/s^2 is the acceleration

Solving for F, we find:

$F=(27)(11550)=311,850 N$

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3 years ago

PLS HELP WILL GIVE 50 POINTS

gregori [183]

Answer:

I'm pretty sure its radiation and reflection. Some of the Sun's energy gets reflected off into space. (I could be wrong though)

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3 years ago

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A. What quantum number of the hydrogen atom comes closest to giving a 61-nm-diameter electron orbit?

Black_prince [1.1K]

Answer:

a

$n = 23$

b

$v = 87377.95 \ m/s$

Explanation:

From the question we are told that

The diameter is $d = 61\ nm = 61 *10^{-9} \ m$

Generally the radius electron orbit is mathematically represented as

$r = \frac{61 *10^{-9}}{2}$

=> $r = 3.05*10^{-8} \ m$

This radius can also be represented mathematically as

$r = n^2 * a_o$

Here n is the quantum number and $a_o$ is the Bohr radius with a value

$a_o = 0.0529 *10^{-9} \ m$

So

$n = \sqrt{\frac{3.05*10^{-8}}{ 0.059*10^{-9}} }$

=> $n = 23$

Generally the angular momentum of the electron is mathematically represented as

$L = m * v * r = \frac{n * h }{2 \pi}$

Here h is the Planck constant and the value is $h = 6.626*10^{-34} J \cdot s$

m is the mass of the electron with values $m = 9.1*10^{-31} \ kg$

So

$v = \frac{23 * 6.626*10^{-34} }{2\pi * 9.1 *10^{-31} * 3.05*10^{-8} }$

$v = 87377.95 \ m/s$

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3 years ago