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oksano4ka [1.4K]
3 years ago
5

Kamala puts on inline skates and stands facing a wall. When she pushes against the wall, she rolls backward. Why does pushing ha

rder make her roll faster?
Physics
2 answers:
Dafna1 [17]3 years ago
7 0
The more force you put in it the farther it will go
nlexa [21]3 years ago
6 0

Answer:

As per Newton's III law every action has equal and opposite reaction.

Explanation:

When Kamala apply force on the wall then equal and opposite force is applied by the wall on Kamala

Due to this reaction force of the wall Kamala moves on her skates in backward direction

Now if Kamala push the wall hard then the reaction force on kamala will be more in magnitude due to which she will roll backward will greater speed as we know that

F = ma

if the reaction force is more then the acceleration will be more so Kamala will roll backward with greater speed

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A mass with a charge of 4.60 x 10-7 C rests on a frictionless surface. A compressed spring exerts a force on the mass on the lef
stira [4]

Answer:

The compression of the spring is 24.6 cm

Explanation:

magnitude of the charge on the left, q₁ = 4.6 x 10⁻⁷ C

magnitude of the charge on the right, q₂ = 7.5 x 10⁻⁷ C

distance between the two charges, r = 3 cm = 0.03 m

spring constant, k = 14 N/m

The attractive force between the two charges is calculated using Coulomb's law;

F = \frac{kq_1q_2}{r^2} \\\\F = \frac{(9\times 10^9)(4.6\times 10^{-7})(7.5\times 10^{-7})}{(0.03)^2} \\\\F= 3.45 \ N

The extension of the spring is calculated as follows;

F = kx

x = F/k

x = 3.45 / 14

x = 0.246 m

x = 24.6 cm

The compression of the spring is 24.6 cm

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3 years ago
Chromosomes are a form of blood cells.
Inessa05 [86]

Answer:

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8 0
3 years ago
Read 2 more answers
A pail of water is rotated in a vertical circle of radius r = 1.6 m . The acceleration of gravity is 9.8 m/s 2 . r v What is the
Snowcat [4.5K]

Answer:3.95 m/s

Explanation:

Given

radius of circle r=1.6 m

Water will not spill if the centripetal acceleration is greater than acceleration due to gravity

i.e. a_c\geq g

a_c=\frac{v^2}{r}

\frac{v^2}{r}\geq g

v_{min}=\sqrt{gr}

v_{min}=\sqrt{9.8\times 1.6}

v_{min}=\sqrt{15.68}

v_{min}=3.95 m/s

8 0
4 years ago
What type of device is a car engine?
34kurt

Answer:

D. a heat engine that uses heat to do work

4 0
3 years ago
A crate of mass 190 kg sits on a horizontal floor. The coefficient of static friction between the crate and the floor is 0.4, an
Oxana [17]

Answer:

Explanation:

Mass of 190kg

Coefficient of static friction is 0.4

Coefficient of kinetic friction 0.36

Horizontal force= 500N

Taking g=9.81m/s^2.

The weight of the body my

W=190×9.81=1863.91N

There is a normal acting on the body which is equal to the weight

N=W=1863.91N

Frictional force(fr) is acting on the body and it is opposite the horizontal force.

The minimum force to be overcome before the object can start to move is Fr = μsN

Fr= μsN. μs=0.4

Fr= 0.4×1863.91

Fr=745.56N.

Since the horizontal force (500N) is not up to the minimum force to make the object move, then the force of 500N the body is still at rest.

Then the frictional force at that time is equal to the horizontal force

Therefore

Functional force = 500N

b. Mass of asteroid is

M=2000kg

Asteroid velocity at a particular instant is,

U=(-1.30x10^4, 4.20x10^4, 0)m/s

Magnitude of U is

U=√(-1.30×10^4)^2 +(4.2×10^4)^2+0

U=√1.933E9

U=4.39×10^4m/s

Position of the asteroid from the centre of the earth is,

R= (6.00x10^6, 10.00x10^6, 0)m.

The magnitude of the radius is

R = √(6.00x10^6)^2+ (10.00x10^6)^2+ 0^2

R=√3.6E13+10E13+0

R=√13.6E13

R=1.17E7m

R^2=13.6E13m

The mass of the earth is

Me=5.97x10^24 kg

The momentum of the asteroid after time, t=1.5×10^3s

Given that G=6.67x10^-11Nm^2/kg^2

Momentum is

Mv-Mu=Ft

There the new momentum will be

Mv=Ft+Mu

Now we the to find the force the earth exert on the asteroid by using

F=GMMe/R^2

F=6.67E-11 ×2000× 5.97E24 /13.6E13

F=7.964E17/13.6E13

F=5855.88N

The new momentum

Mv= Mu+Ft

Mv= 2000(4.39E4)+5855.88(1.5E3)

Mv=9.66E7kgm/s

The new momentum is 9.66×10^7 Kgm/s

8 0
3 years ago
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