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oksano4ka [1.4K]
3 years ago
5

Kamala puts on inline skates and stands facing a wall. When she pushes against the wall, she rolls backward. Why does pushing ha

rder make her roll faster?
Physics
2 answers:
Dafna1 [17]3 years ago
7 0
The more force you put in it the farther it will go
nlexa [21]3 years ago
6 0

Answer:

As per Newton's III law every action has equal and opposite reaction.

Explanation:

When Kamala apply force on the wall then equal and opposite force is applied by the wall on Kamala

Due to this reaction force of the wall Kamala moves on her skates in backward direction

Now if Kamala push the wall hard then the reaction force on kamala will be more in magnitude due to which she will roll backward will greater speed as we know that

F = ma

if the reaction force is more then the acceleration will be more so Kamala will roll backward with greater speed

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The period of a sound wave coming from an instrument is 0. 002 seconds. What is the frequency of the sound? Hz.
Pie

The period is the time taken by the wave to complete an oscillation. The frequency of the given sound is 500 Hz.

<h2>Period:</h2>

It is the time taken by the wave to complete an oscillation. The frequency is inversely proportional to the time:

f = \dfrac 1T

Where,

f- frequency

T - period = 0.002 s

Put the value in the equation,

f = \dfrac 1{0.002}\\\\f = 500\rm \  Hz

Therefore, the frequency of the given sound is 500 Hz.

Learn more about Period:

brainly.com/question/842349

5 0
2 years ago
Can someone help with this???
Rus_ich [418]

no BECQUSE POSUM BROOB SHSHSJ

8 0
3 years ago
Read 2 more answers
A gas is compressed from an initial volume of 5.75 L to a final volume of 1.23 L by an external pressure of 1.00 atm. During the
nataly862011 [7]

Answer:

<em>The internal energy change is 330.01 J</em>

Explanation:

Given

v_{1} the initial volume = 5.75 L

v_{2} the final volume = 1.23 L

P_{e} is the external pressure = 1.00 atm

q the heat energy removed = -128 J (since is removed from the system)

expansion against a constant external pressure is an example of an irreversible pathway, here pressure in is greater than pressure out and can be obtained thus;

W = -P_{e}ΔV

W = -1.00 x(1.23 - 5.75)

W =  -1.00 x -4.52

W = 4.52 L atm

converting to joules we have

W = 4.52 L atm x 101.33 J/ L atm = 458.01 J

The internal energy change during compression can be calculated thus;

ΔU = q + W

ΔU = -128 J + 458.01 J

ΔU = 330.01 J

Therefore the internal energy change is 330.01 J

8 0
2 years ago
A man walks 40 m North, then 70 m East and then 40
Anastasy [175]

Answer:

Displacement = 70 m towards east

Explanation:

Displacement is the shortest distance between the two points.

Let us say that he starts at the point O and travels in a path ABC.

If we join the initial and final point of the path travelled by him, it will give the displacement of the man.

Distance from O to A = 40 m

Distance from A to B = 70 m

Distance from B to C = 40 m

Distance from O to A = Distance from B to C

We want the displacement which is distance between the points O and C

In rectangle opposite sides are equal. Hence Distance from O to C = Distance from A to B

Displacement = Distance from A to B

Hope it helps,

Please mark me as the brainliest.

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4 0
3 years ago
Read 2 more answers
A 75.0kg bicyclist (including the bicycle) is pedaling to the right, causing her speed to increase at a rate of 2.20m/s^2, despi
malfutka [58]

1) 4 forces

2) 165 N

3) 225 N

Explanation:

1)

There are in total 4 forces acting on the bicylist:

- The gravitational force on the byciclist, acting vertically downward, of magnitude mg, where m is the mass of the bicyclist and g is the acceleration due to gravity

- The normal force exerted by the floor on the bicyclist and the bike, N, vertically upward, and of same magnitude as the gravitational force

- The force of push F, acting horizontally forward, given by the push exerted by the bicylist on the pedals

- The air drag, R, of magnitude R = 60.0 N, acting horizontally backward, in the direction opposite to the motion of the bicyclist

2)

The magnitude of the net force on the bicyclist can be calculated by considering separately the two directions.

- Along the vertical direction, we have the gravitational force (downward) and the normal force (upward); these two forces are equal in magnitude, since the acceleration of the bicyclist along this direction is zero, therefore the net force in this direction is zero.

- Along the horizontal direction, the two forces (forward force of push and air drag) are balanced, since the acceleration is non-zero, so we can use Newton's second law of motion to find the net force on the bicylist:

F_{net}=ma

where

F_{net} is the net force

m = 75.0 kg is the mass of the bicyclist

a=2.20 m/s^2 is its acceleration

Solving, we find the net force:

F_{net}=(75.0)(2.20)=165 N

3)

In this part, we basically want to find the forward force of push, F.

We can rewrite the net force acting on the bicyclist as

F_{net}=F-R

where:

F is the forward force of push

R is the air drag

We know that:

F_{net}=165 N is the net force on the bicyclist

R = 60.0 N is the magnitude of the air drag

Therefore, by re-arranging the equation, we can find the force generated by the bicylicst by pedaling:

F=F_{net}+R=165+60=225 N

6 0
3 years ago
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