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3 years ago

Compare an oxygen particle to a water particle. In your answer , include describing how they are different and similar.

Chemistry

1 answer:

Naddik [55]3 years ago

5 0

Answer:

An oxygen molecule consists of two oxygen (o2) atoms bound together and a water molecule consists of two hydrogen atoms and one oxygen atom (h20). H20 has a higher evaporation temperature than oxygen therefore it stays a liquid at room temperature unlike oxygen. Both have oxygen atoms.

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Refer to the picture given below to give the answer. Don’t forget to use the correct amount of sig figs.

kumpel [21]

Answer:

9.62 μm

Explanation:

From the question given above, the following data were obtained:

Frequency (f) = 31.2 THz

Wavelength (λ) =..?

Next, we shall convert 31.2 THz to Hz.

This can be obtained as follow:

Recall:

1 THz = 1×10¹² Hz

Therefore,

31.2 THz = 31.2 THz × 1×10¹² Hz / 1 THz

31.2 THz = 3.12×10¹³ Hz

Therefore, 31.2 THz is equivalent to 3.12×10¹³ Hz.

Finally, we shall determine the wavelength (λ) infrared radiation as follow:

Frequency (f) = 3.12×10¹³ Hz.

Velocity (v) = 3×10⁸ m/s

Wavelength (λ) =..?

V = λf

3×10⁸ = λ × 3.12×10¹³

Divide both side by 3.12×10¹³

λ = 3×10⁸ / 3.12×10¹³

λ = 9.62×10¯⁶ m

Converting 9.62×10¯⁶ m to micro metre (μm) we have:

1 m = 1×10⁶ μm

Therefore,

9.62×10¯⁶ m = 9.62×10¯⁶ m × 1×10⁶ μm / 1 m

9.62×10¯⁶ m = 9.62 μm

Therefore, the wavelength of the infrared radiation is 9.62 μm

7 0

3 years ago

This element is often used to block out dangerous radiation.

ella [17]

Lead is often used to block out radiation

7 0

4 years ago

Please hurry I’m stuck!!

MakcuM [25]

Answer:

Explanation:

C+O2=CO2

5 0

3 years ago

Read 2 more answers

Use the information in the table about four different electric circuits to answer the question

ycow [4]

Answer:

Circuit 4

Explanation:

To know the correct answer to the question given above, we shall determine the current in each circuit. This can be obtained as follow:

For circuit 1:

Resistance (R) = 0.5 ohms

Voltage (V) = 20 V

Current (I) =?

V = IR

20 = I × 0.5

Divide both side by 0.5

I = 20 / 0.5

I = 40 A

For circuit 2:

Resistance (R) = 0.5 ohms

Voltage (V) = 40 V

Current (I) =?

V = IR

40 = I × 0.5

Divide both side by 0.5

I = 40 / 0.5

I = 80 A

For circuit 3:

Resistance (R) = 0.25 ohms

Voltage (V) = 40 V

Current (I) =?

V = IR

40 = I × 0.25

Divide both side by 0.25

I = 40 / 0.25

I = 160 A

For circuit 4:

Resistance (R) = 0.25 ohms

Voltage (V) = 60 V

Current (I) =?

V = IR

60 = I × 0.25

Divide both side by 0.25

I = 60 / 0.25

I = 240 A

SUMMARY

Circuit >>>>>> Current

1 >>>>>>>>>>> 40 A

2 >>>>>>>>>>> 80 A

3 >>>>>>>>>>> 160 A

4 >>>>>>>>>>> 240 A

From the above calculation, circuit 4 has the greatest electric current.

8 0

3 years ago

Which shows an isomer of the molecule below?

babunello [35]

Above question is incomplete. Complete question is attached below
.......................................................................................................................

Correct Answer: Option D i.e. CH3CH2CH2CH2CH3

Reason:
Isomers are the compounds having same molecular formula, but different structural formula.

The molecular formula of the compound is C5H12

The compound present is question (i.e. 2-methyl butane) and option D (n-pentane) has same molecular formula. Hence, they are isomers.

However, compound present in option A, is the same compound provided in question. Hence, it is not an isomer. Compounds reported in option B and C has one carbon atom less and more, respectively as compared to the compound reported in question. Hence, they are also not isomers.

5 0

3 years ago