Answer : The final temperature of the solution in the calorimeter is,
Explanation :
First we have to calculate the heat produced.
where,
= enthalpy change = 82.8 kJ/mol
q = heat released = ?
m = mass of = 5.10 g
Molar mass of = 110.98 g/mol
Now put all the given values in the above formula, we get:
Now we have to calculate the final temperature of solution in the calorimeter.
where,
q = heat produced = 3.80 kJ = 3800 J
m = mass of solution = 100 + 5.10 = 105.10 g
c = specific heat capacity of water =
= initial temperature =
= final temperature = ?
Now put all the given values in the above formula, we get:
Thus, the final temperature of the solution in the calorimeter is,
Answer: Hydrogen belongs to group 1 metal elements in the periodic table.
Explanation:
The hydrogen is a highly active metal. It has a single electron in its valence shell and it can donate its electron to other metal atoms. Thus forming metal hydrides. The hydrogen when ignited it reacts with oxygen and burns explosively this is indicative of high reactivity and spontaneous reactivity of hydrogen atom.
the answer to your question is
ρ≅13.0⋅g⋅mL−1 = 13.0⋅g⋅cm−3Explanation:Density=Mass Per unit Volume = 75.0⋅g(36.5−31.4)⋅mL =??g⋅mL−1Note that 1⋅mL = 1⋅cm−3; these are equivalent units of volume; i.e. 1⋅cm3 = 1×(10−2⋅m)3=1×10−6⋅m3=10−3⋅L=1⋅mL.
1. B, helium
2. B, carbs-lipids-nucleic acids-proteins
hope I helped
Answer:- 4.35 kg of ammonium perchlorate are required for every kg of Al.
Solution:- It's a stoichiometry problem. The balanced equation for this problem is....
From balanced equation, there is 3:3 that is 1:1 mol ratio between aluminum and ammonium perchlorate.
Given mass of Al is 1 kg and we are asked to calculate the mass of ammonium perchlorate for it.
Molar mass of Al is 26.98 g/mol and molar mass of ammonium perchlorate is 117.49 g/mol.
1 kg = 1000 g
Grams of Al are converted to moles and then moles of ammonium perchlorate are calculated using mol ratio and finally on multiplying with molar mass we get the mass of ammonium perchlorate.
1000 g Al x (1mol Al/26.98 g Al) (1mol ammonium perchlorate/1mol Al) (117.49 g ammonium perchlorate/1mol ammonium perchlorate)
= 4354.7 g that is 4.35 kg of ammonium perchlorate