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3 years ago

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a lizard drinks water that contains H-2. The H-2 decays and approximately 6.25% remain after 30 seconds. What is the 1/2 life fo

r H-2?

1 answer:

den301095 [7]3 years ago

3 0

Answer:

7.5 sec.

Explanation:

A = A₀e⁻^kt => k = ln(A/A₀)/-t => ln(6.25/100)/-30s = 0.0924 s⁻¹

k·t₀.₅=0.693 => t₀.₅=0.693/k = (0.693/0.0924)s = 7.5 s

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You will first investigate 5 diatomic molecules. Diatomic molecules are made up of 2 atoms.

GenaCL600 [577]

Answer:

Here's what I get

Explanation:

1. Fluorine

a. Each fluorine atom has seven valence electrons.

b. Fluorine is a nonmetal.

c. The combination of these atoms creates a covalent bond.

d. The atoms share a pair of valence electrons.

e. In the ionic bond, an electron moved from one atom to the other one.

f. The molecule forms a straight line.

2. Oxygen

a. Each oxygen atom has six valence electrons.

b. Oxygen is a nonmetal.

c. The combination of these atoms creates a covalent bond.

d. The atoms share two pairs of valence electrons.

e. The bond has four electrons instead of two.

f. The molecule forms a straight line.

8 0

3 years ago

DA gas has a volume of 4.00 L at 0 degrees Celsius. What final temperature, in degrees Celsius, is needed to change the volume o

Sholpan [36]

D 50.O ML IS THE ANSWER

6 0

4 years ago

Determine the mass of water produced from 50g hydrochloric acid and

Alenkinab [10]

Answer:

24.7 grams H₂O

Explanation:

To find the mass of water, you should (1) convert from grams HCl to moles (via molar mass from periodic table), then (2) convert from moles HCl to moles H₂O (via mole-to-mole ratio from equation), and then (3) convert from moles H₂O to grams (via molar mass from periodic table).

1 HCl + KOH --> 1 H₂O + KCl

Molar Mass (HCl): 1.008 g/mol + 35.45 g/mol
Molar Mass (HCl): 36.458 g/mol

Molar Mass (H₂O): 2(1.008 g/mol) + 16.00 g/mol
Molar Mass (H₂O): 18.016 g/mol

50 g HCl 1 mole HCl 1 mole H₂O 18.016 g
-------------- x ------------------ x ------------------- x ------------------- = 24.7 g H₂O
36.458 g 1 mole HCl 1 mole H₂O

3 0

2 years ago

Name the following compound: CH3 – CH2 – CH2 – CH2 – CH2 – CH2 – CH2 – CH3 octyle octyne octane octene

ad-work [718]

8 carbons is "oct" prefix (like polygons)
No pi bonds is "ane" suffix.

put it together to get.... Octane

6 0

3 years ago

Read 2 more answers

A compound is 21.6% Mg, 21.4% C, and 57.0% O. What is the empirical formula of the compound?

nignag [31]

Answer:

Compound x = $MgC_{2}O_{4}$

Explanation:

Let the compound be x

Assuming we have a 100g of compound x

<u>Given the following data;</u>

Magnesium, Mg = 21.6% = 21.6g

Carbon, C = 21.4% = 21.4g

Oxygen, O = 57.0% = 57.0g

Now, we would find the amount of moles for each element.

Atomic mass of Mg = 24.30g

Atomic mass of C = 12.01g

Atomic mass of O = 16.00g

<u>Amount of moles for Mg;</u>

21.6*(1/24.30) = 0.89mol

<u>Amount of moles for C;</u>

21.4*(1/12.01) = 1.78mol

<u>Amount of moles for O;</u>

57.0*(1/16.00) = 3.56mol

We then divide by the smallest to find the ratio;

0.89/0.89 = 1 Mol of Mg

1.78/0.89 = 2 Mol of C

3.56/0.89 = 4 Mol of O

Therefore, the ratio of Mg, C and O is 1:2:4.

Compound x = $MgC_{2}O_{4}$

Hence, the empirical formula of the compound is $MgC_{2}O_{4}$

7 0

3 years ago