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3 years ago

If 225 grams of propane are burned in the presence of 125 grams of oxygen, how many grams of water should be expected?

1 answer:

5 0

150 grams of water because if 225 grams of propane are burned with 125 grams of oxyegen then there will be 150 grams of water

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what is the molarity of an HCI solution if 25.0 ml of 0.185 M NaOH is required to neutralize 0.0200 L of HCI?

butalik [34]

Answer:

Molarity of HCl solution = 0.25 M

Explanation:

Given data:

Volume of NaOH= V₁ = 25.0 mL (25/1000 = 0.025 L)

Molarity of NaOH solution=M₁ = 0.185 M

Volume of HCl solution = V₂ = 0.0200 L

Molarity of HCl solution = M₂= ?

Solution:

M₁V₁ = M₂V₂

0.185 M ×0.025 L = M₂ × 0.0200 L

M₂ = 0.185 M ×0.025 L / 0.0200 L

M₂ = 0.005M.L /0.0200 L

M₂ = 0.25 M

7 0

3 years ago

10 points get it right ADVPH

Sav [38]

Answer:

Advanced Pharmaceutics Inc

Explanation:

Advanced Pharmaceutics Inc

somehow I know this acroynom

8 0

3 years ago

Acetylene gas, C2H2, releases large quantities of heat when it burns, making it ideal for welding applications. This gas is gene

Karo-lina-s [1.5K]

Answer:

64 kg

Explanation:

The computation of the number of kg need to ordered is shown below:

As we know that

$CaC_2 + 2H_2O \rightarrow Ca(OH)^2 + C_2H_2$

Now as we know that

1 mole of $C_2H_2$ generated from 1 mole of $CaC_2$

Now

26g of $C_2H_2$ generated from 64g of $CaC_2$

And,

26kg of $C_2H_2$ generated from

= $\frac{64g\times26Kg}{26g}$

= 64kg $CaC_2$

Hence, the number of kg that required for ordering the calcium carbide is 64 kg

5 0

3 years ago

A piston containing 0.120moles of methane gas, CH4, has a volume of 2.12liters. If methane is added until the volume is increase

earnstyle [38]

Answer:

2.83 g

Explanation:

At constant temperature and pressure, Using Avogadro's law

$\frac {V_1}{n_1}=\frac {V_2}{n_2}$

Given ,

V₁ = 2.12 L

V₂ = 3.12 L

n₁ = 0.120 moles

n₂ = ?

Using above equation as:

$\frac{2.12}{0.120}=\frac{3.12}{n_2}$

$2.12n_2=0.12\cdot \:3.12$

$2.12n_2=0.3744$

$n_2=\frac{0.3744}{2.12}$

$n_2=0.17660$

n₂ = 0.17660 moles

Molar mass of methane gas = 16.05 g/mol

So, Mass = Moles*Molar mass = 0.17660 * 16.05 g = 2.83 g

<u>2.83 g are in the piston.</u>

8 0

4 years ago

Which has a larger radius f or -f

Kipish [7]

Since f is positive I would say f

3 0

3 years ago

Read 2 more answers