Answer:
The HNO3 solution has a concentration of 0.07 M
Explanation:
<u>Step 1:</u> find a balanced equation
HNO3 (aq) + NaOH (aq) → NaNO3 (aq) + H2O (l)
⇒ for 1 mole of HNO3 reacted, there will also react 1 mole of NaOH, and be produced 1 mole of NaNO3 and 1 mole of H2O, since the ratio is 1:1
<u>Step 2:</u> Calculating moles
Since we know that for 1 mole of HNO3 there will react 1 mole of NaOH, we can calculate the number of moleNaOH
⇒ Concentration = mole / volume
⇒ 0.210 = mole / ((20 + 7.23 ml) *10^-3)
mole = 0.005733 mole NaOH = 0.005733 mole HNO3
<u>Step 3:</u> Calculating the concentration of HNO3
Concentration = mole / volume
C(HNO3) = 0.005733 mole / ((50 + 30 ml) *10^-3)
C(HNO3) = 0.07 M
The HNO3 solution has a concentration of 0.07 M
To control this we can calculate through the following formule:
0.02723L x 0.21 M x ( 1mol HNO3 / 1 mol NaOH) x (1/ 0.08L) = 0.07M
