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yuradex [85]
3 years ago
11

If 225 grams of propane are burned in the presence of 125 grams of oxygen, how many grams of water should be expected?

Chemistry
1 answer:
Travka [436]3 years ago
5 0
150 grams of water because if 225 grams of propane are burned with 125 grams of oxyegen then there will be 150 grams of water

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Al2(SO4)3+Mg(NO3)2⟶ What would be the product(s) of this reaction? *These are NOT balanced, just look for the correct products*
Readme [11.4K]

Answer:

Al_2(SO_4)_3+3Mg(NO_3)_2\rightarrow 2Al(NO_3)_3+3MgSO_4

Explanation:

Hello there!

In this case, for the given reactants side, we infer this is a double replacement reaction because all the cations and anions are switched around as a result of the chemical change, we infer that the products side include aluminum with nitrate and magnesium with sulfate as shown below:

Al_2(SO_4)_3+Mg(NO_3)_2\rightarrow Al(NO_3)_3+MgSO_4

However, we need to balance since unequal number of atoms are present at both sides, thus, we do that as shown below:

Al_2(SO_4)_3+3Mg(NO_3)_2\rightarrow 2Al(NO_3)_3+3MgSO_4

Thus, we make 6 Al atoms, 3 S atoms, 3 Mg atoms and 30 O atoms on each side in agreement with the law of conservation of mass.

Regards!

7 0
3 years ago
Why do you think that the electrons are not shown?
snow_lady [41]
Because there to tiny to see
7 0
3 years ago
6.75 L of carbon dioxide gas are stored at a pressure of 175 atm. If the temperature and number of gas particles do not change,
I am Lyosha [343]

Answer:

4.24 L

Explanation:

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x. - 110 atm

  • <u>175atm </u><u>x</u>=<u>742.5L /atm</u>

175atm 175atm

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3 0
3 years ago
What is the molality of a solution that is obtained by dissolving 2.922 g of NaCl into 1000.0 g of water if the molar mass of Na
never [62]
In order to find molarity, you must first find the number of moles that was dissolved.

Now, Moles = Mass ÷ Molar Mass
                   
⇒  Moles of NaCl  = 2.922 g ÷ 58.44 g/mol 
                       
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∴ the Molarity of the NaCl is 0.05 M [Option 1]
4 0
3 years ago
Calculate the [oh−] in a solution with a ph of 12.52.
BaLLatris [955]
PH + pOH = 14

12.52 + pOH = 14

pOH = 14 - 12.52

pOH = 1.48

[OH⁻] = 10^ -pOH

[OH⁻] = 10 ^- 1.48

[OH⁻] = 0.033 M
6 0
3 years ago
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