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It is just based on the fact that they are closer or further away from the Sun.
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Given :
Molarity of sulfuric acid solution is 3.0 M.
Amount of sulfuric acid present in solution is 9.809 g.
To Find :
The volume of solution.
Solution :
We know, molarity is given by :

Therefore, volume required is 33.33 ml .
Answer:
[Cl⁻] = 0.016M
Explanation:
First of all, we determine the reaction:
Pb(NO₃)₂ (aq) + MgCl₂ (aq) → PbCl₂ (s) ↓ + Mg(NO₃)₂(aq)
This is a solubility equilibrium, where you have a precipitate formed, lead(II) chloride. This salt can be dissociated as:
PbCl₂(s) ⇄ Pb²⁺ (aq) + 2Cl⁻ (aq) Kps
Initial x
React s
Eq x - s s 2s
As this is an equilibrium, the Kps works as the constant (Solubility product):
Kps = s . (2s)²
Kps = 4s³ = 1.7ₓ10⁻⁵
4s³ = 1.7ₓ10⁻⁵
s = ∛(1.7ₓ10⁻⁵ . 1/4)
s = 0.016 M
Answer:
A) litmus is red
Explanation:
To answer this question, it can be helpful to have the color charts. Litmus, phenolphthalein and methyl orange are ways to test the pH of a substance.
<u>Litmus paper</u>
Litmus can tell you if a substance is an acid or a base. You need to put the substance on both red litmus and blue litmus paper.
pH < 7: both papers are red. 3.0 is less than 7.
pH = 7: none of them change color
pH > 7: both papers are blue
<u>Phenolphthalein</u>
When this indicator is added to a substance, the result is either colorless or pink.
0 < pH ≤ 7: colorless. The color is not red or blue for pH 3.0.
pH > 7: pink
<u>Methyl orange</u>
0 < pH < 4: red. The color is not yellow if the pH is 3.0.
4 ≤ pH < 5: orange
pH ≥ 5: yellow
<u>Answer:</u> The correct answer is 
<u>Explanation:</u>
We are given:

The substance having highest positive
potential will always get reduced and will undergo reduction reaction. Here, silver will always undergo reduction reaction will get reduced.
Chromium will undergo oxidation reaction and will get oxidized.
The half reactions for the above cell is:
Oxidation half reaction: 
Reduction half reaction:
( × 3)
Net equation: 
Oxidation reaction occurs at anode and reduction reaction occurs at cathode.
To calculate the
of the reaction, we use the equation:

Putting values in above equation, we get:

Hence, the correct answer is 