The mole fraction of acetone (C₃H₆O) is 0.333
<h3>Data obtained from the question </h3>
- Mole of C₃H₆O = 0.1 mole
- Mole of CHCl₃ = 0.2 mole
- Mole fraction of C₃H₆O =?
<h3>How to determine the mole fraction </h3>
Mole fraction of a substance can be obtained by using the following formula:
Mole fraction = mole / total mole
With the above formula, we can obtain the mole fraction of C₃H₆O as follow:
- Mole of C₃H₆O = 0.1 mole
- Mole of CHCl₃ = 0.2 mole
- Total mole = 0.1 + 0.2 = 0.3 mole
- Mole fraction of C₃H₆O =?
Mole fraction = mole / total mole
Mole fraction of C₃H₆O = 0.1 / 0.3
Mole fraction of C₃H₆O = 0.333
Learn more about mole fraction:
brainly.com/question/2769009
Answer:
Enthalpy of vaporization = 30.8 kj/mol
Explanation:
Given data:
Mass of benzene = 95.0 g
Heat evolved = 37.5 KJ
Enthalpy of vaporization = ?
Solution:
Molar mass of benzene = 78 g/mol
Number of moles = mass/ molar mass
Number of moles = 95 g/ 78 g/mol
Number of moles = 1.218 mol
Enthalpy of vaporization = 37.5 KJ/1.218 mol
Enthalpy of vaporization = 30.8 kj/mol
Organism are made up of organic molecules consisting of carbon, hydrogen, oxygen, nitrogen, sulfur, and phosphorus.
The answer is B.
