How many moles of methanol must be burned to release 1454 KJ of energy

Chemistry

1 answer:

ra1l [238]3 years ago

6 0

A lot of moles ya know but moles need sticks. Big sticks equals big moles and big moles equal for me 5 points

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If 11.5 ml of vinegar sample (d=1g/ml) is titrated with 18.5 ml of standardized Sodium hydroxide

insens350 [35]

Answer:

4.83% of acetic acid in the vinegar

Explanation:

3 0

3 years ago

A 26.08 g mixture of zinc and sodium is reacted with a stoichiometric amount of sulfuric acid. The reaction mixture is then reac

Over [174]

Answer:

Molar percent of sodium in original mixture is 88,50%

Explanation:

The last reaction is:

BaCl₂ + Na₂SO₄ → BaSO₄ + 2 NaCl

The moles of BaCl₂ are:

0,132L × 3,80M = 0,502 moles of BaCl₂

As the amount of BaCl₂ is the maximum possible to produce BaSO₄, the moles of BaCl₂ must be the same than moles of Na₂SO₄.

0,502 moles of BaCl₂ ≡ 0,502 moles of Na₂SO₄

These moles of Na₂SO₄ comes from:

2 Na + H₂SO₄ → Na₂SO₄ + H₂

As the reaction is in stoichiometric amounts, moles of Na are twice the moles of Na₂SO₄

0,502 moles of Na₂SO₄ × $\frac{2molesNa}{1moleNa_{2}SO_{4}}$ × 22,99 g/mole = 23,08 g of Na

Molar percent of sodium in original mixture is:

$\frac{23,08g}{26,08g}*100$ = 88,50%

I hope it helps

4 0

3 years ago

Compare and contrast: element, atom, isotope

blsea [12.9K]

Answer:

Element is made up of the atoms or isotopes. Isotopes are where only neutrons change in number, such as 3 turning to 2 or to 5. Atom is where it is not changed and it is the original, and example is instead of Carbon13 it is just Carbon. I hope this helps.

7 0

3 years ago

Read 2 more answers

Show the mechanism for the following reaction conducted at –5 °C in CCl4: cyclohexene bromine yields a dibromocyclohexane Draw w

Darya [45]

Answer:

See attachment.

Explanation:

In the first step, a cyclic structure with a positive bromine is formed. The bromine shares the positive charge with the two carbons that it is bonded to, so the carbons are partially positive.

The second bromine atom then attacks the carbon center, coming in from below the first bromine atom ("backside attack") where the antibonding orbital of the second bromine atom is.

The stereochemistry of the mechanism causes the final product to be an anti-dibromocyclohexane.