Ask question

Ask question

All categories

2 years ago

10

Max buys six donuts and a 300ml carton of juice for $3.50,susie buys four donuts and two 300ml carton of juice for $3.00,ben buy

s eight donuts and one 300ml carton of juice for $6.50 How much is one donut? How much is one carton of drink?

1 answer:

frutty [35]2 years ago

8 0

Answer:

l think the dount 1.00 and the cartton juic 2.99

Step-by-step explanation:

im not sure

You might be interested in

Solve for x in the triangle. Round your answer to the nearest tenth.

wariber [46]

Answer:

the answer is 12

i used 5 12 13 special trangle

and there is 2 angle 56 and 34

so the biggest angle meet the 12

and the little angle meet the 5

hopefully its correct

5 0

2 years ago

Which describes the<br> correlation shown in the scatterplot? help pls

Yuri [45]

Answer:

B

Step-by-step explanation:

There is a negative correlation. The direction of a line if we plot it generally through thi scatter plot would be going down, negative.

5 0

2 years ago

Read 2 more answers

Identify the expression with nonnegative limit values. More info on the pic. PLEASE HELP.

marshall27 [118]

Answer:

$\lim _{x\to 2}\:\frac{x-2}{x^2-2}\\\\ \lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}\\\\ \lim _{x\to \frac{5}{2}}\left\frac{2x^2+x-15}{2x-5}\right$

Step-by-step explanation:

a) $\lim _{x\to 3}\:\frac{x^2-10x+21}{x^2+4x-21}=\lim \:_{x\to \:3}\:\frac{\left(x-7\right)\left(x-3\right)}{\left(x+7\right)\left(x-3\right)}=\lim \:_{x\to \:3}\:\frac{x-7}{x+7}=\frac{3-7}{3+7}=-\frac{4}{10}=-\frac{2}{5}$

b) $\lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=\lim \:_{x\to -\frac{3}{2}}\:\frac{\left(2x+3\right)\left(x-4\right)}{\left(2x+3\right)}=\lim \:\:_{x\to \:-\frac{3}{2}}\:\left(x-4\right)=-\frac{3}{2}-4\\ \\ \lim _{x\to -\frac{3}{2}}\left(\frac{2x^2-5x-12}{2x+3}\right)=-\frac{11}{2}$

c) $\lim _{x\to 2}\:\frac{x-2}{x^2-2}=\frac{2-2}{\left(2\right)^2-2}=\frac{0}{4-2}=0$

d) $\lim _{x\to 11}\:\frac{x^2+6x-187}{x^2+3x-154}=\lim _{x\to 11}\:\frac{\left(x-11\right)\left(x+17\right)}{\left(x-11\right)\left(x+14\right)}=\lim _{x\to 11}\:\frac{\left(x+17\right)}{\left(x+14\right)}=\frac{11+17}{11+14}=\frac{28}{25}$

e) $\lim _{x\to 3}\:\frac{x^2-8x+15}{x-3}=\lim \:_{x\to \:3}\:\frac{\left(x-3\right)\left(x-5\right)}{x-3}=\lim _{x\to 3}\left(x-5\right)=3-5=-2$

f) $\lim _{x\to \frac{5}{2}}\left(\frac{2x^2+x-15}{2x-5}\right)=\lim \:_{x\to \:\frac{5}{2}}\frac{\left(2x-5\right)\left(x+3\right)}{2x-5}=\lim \:\:_{x\to \:\:\frac{5}{2}}\left(x+3\right)=\frac{5}{2}+3=\frac{11}{2}$

4 0

2 years ago

Clara asked her coworkers about how much time they spent commuting each morning. This box-and-whisker plot shows the results.

blondinia [14]

I think the 40 30 20 should be going up not down like this 20 30 40

6 0

3 years ago

PLEASE HELP!! Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match the trigonometric rat

Monica [59]

this is the answer on edmentum

6 0

2 years ago