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Sedaia [141]
3 years ago
13

HURRY!!!!

Physics
2 answers:
nevsk [136]3 years ago
7 0

Answer:

light strikes the grooves → different wavelengths of light bend at different angles → diffracted wavelength reach the eyes → the eyes see different colors

Explanation:

A light is a combination of colors which can be separated appropriately by the use of diffraction grating. Diffraction grating is an optical device that splits and diffracts light into several beams and colors with respect to their wavelength. The size of the grooves  and wavelength determine the direction of dispersion.

Bingel [31]3 years ago
4 0
I'm not exactly sure but I'm thinking that it's the last one. Sorry if I'm wrong
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Arbeitsauftrag 2
kramer

Explanation:

<em>The height of the pendulum is measured from the lowest point it reaches (point 3). </em>

At 1, the kinetic energy of the pendulum is zero (because it is not moving), and it has maximum potential energy.

At 2, the pendulum has both kinetic and potential energy, and how much of each it has depends on its height—smaller the height greater the kinetic energy and lower the potential energy.

At 3, the height is zero; therefore, the pendulum has no potential energy, and has maximum kinetic energy.

At 4, the pendulum again gains potential energy as it climbs back up,  Again how much of each forms of energy it has depends on its height.

At 5, the maximum height is reached again; therefore, the pendulum has maximum potential energy and no kinetic energy.

Hope this helps :)

8 0
3 years ago
A charged wire of negligible thickness has length 2L units and has a linear charge density λ. Consider the electric field E-vect
Stels [109]

Answer:

E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}

Explanation:

Given that

Length= 2L

Linear charge density=λ

Distance= d

K=1/(4πε)

The electric field at point P

E=2K\int_{0}^{L}\dfrac{\lambda }{r^2}dx\ sin\theta

sin\theta =\dfrac{d}{\sqrt{d^2+x^2}}

r^2=d^2+x^2

So

E=2K\lambda d\int_{0}^{L}\dfrac{dx }{(x^2+d^2)^{\frac{3}{2}}}

Now by integrating above equation

E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}

4 0
3 years ago
If youre reading this goodluck in school homie &lt;3
bazaltina [42]
I needed this ! Thanks a lot
7 0
3 years ago
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