Given :
Initial speed , u = 0 m/s .
Final speed , v = 91 km/h = 25.28 m/s .
To Find :
a) Average acceleration .
b ) Assuming the motorcycle maintained a constant acceleration, how far is it from the traffic light after 3.3 s .
Solution :
a )
We know ,by equation of motion :
b)
Also , by equation of motion :
Hence , this is the required solution .
Answer:
Angular acceleration of the disc just after the release is given as
Explanation:
Here we know that the disc is hinged about the center and hence the weight of two particles will apply torque on the disc in opposite directions
So here net torque on the disc at the given position is
now total moment of inertia of the system of the disc is given as
now we have
so we have
so we have
Answer:
Average speed, v = 11.37 m/s
Explanation:
Given that,
The distance covered by the traveler, d = 217 miles = 349228 meters
Time taken,
or t = 30708 s
We need to find the average speed for this trip. The average speed is given by :
v = 11.37 m/s
So, the average speed for this trip is 11.37 m/s. Hence, this is the required solution.
Answer:
At twice the distance, the strength of the field is e/4
Explanation:
F = the strength of an electric field.
F is inversely proportional to the squared distance from the point charge.
mathematically,
F = k(e/d²)
hence, if d is doubled,keeping other forms constant
F = e/4,
Boiling water has a lot more heat than the oven's air (even though the air has a higher temperature). ... A match has a greater temperature than the iceberg because the average molecule in the match is moving faster than the average molecule in the iceberg