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arsen [322]
3 years ago
13

Which equation represents positron decay?

Chemistry
1 answer:
jonny [76]3 years ago
8 0

Answer: 4

Explanation:

4 is the only one that has to products as well as having the plus at the bottom

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C9H20 +<br> 02 - &gt; CO2 +<br> H2O<br><br> what is the balanced equation of this
san4es73 [151]

Hey there!

C₉H₂O + O₂ → CO₂ + H₂O

First let's balance the C.

There's 9 on the left and 1 on the right. So, let's add a coefficient of 9 in front of CO₂.

C₉H₂O + O₂ → 9CO₂ + H₂O

Next let's balance the H.

There's 2 on the left and 2 on the right. This means it's already balanced.

C₉H₂O + O₂ → 9CO₂ + H₂O

Lastly, let's balance the O.

There's 3 on the left and 19 on the right. So, let's add a coefficient of 9 in front of O₂.

C₉H₂O + 9O₂ → 9CO₂ + H₂O

This is our final balanced equation.

Hope this helps!

8 0
3 years ago
Which of the following is not a reason for extinction?
Rashid [163]

Answer:

the ability to breed successfully

Explanation:

3 0
3 years ago
Read 2 more answers
(05.02 LC)<br><br> How many moles of each element are in one mole of Sr(HCO3)2? (3 points)
Nina [5.8K]

Answer:

The number of moles of Sr in one mole of Sr(HCO₃)₂ = 1 mole

The number of moles of H in one mole of Sr(HCO₃)₂ = 2 moles

The number of moles of C in one mole of Sr(HCO₃)₂ = 2 moles

The number of moles of O in one mole of Sr(HCO₃)₂ = 6 moles

Explanation:

The given chemical formula of the compound is Sr(HCO₃)₂

The number of atoms of Sr in the compound = 1

The number of atoms of H in the compound = 2

The number of atoms of C in the compound = 2

The number of atoms of O in the compound = 6

The number of atoms of each element present in each formula unit of Sr(HCO₃)₂ is proportional to the number of moles of each atom in one mole of Sr(HCO₃)₂

Therefore;

The number of moles of Sr in one mole of Sr(HCO₃)₂ = 1 mole

The number of moles of H in one mole of Sr(HCO₃)₂ = 2 moles

The number of moles of C in one mole of Sr(HCO₃)₂ = 2 moles

The number of moles of O in one mole of Sr(HCO₃)₂ = 6 moles.

5 0
3 years ago
A student is given a sample of a blue copper sulfate hydrate. He weighs the sample in a dry covered porcelain crucible and got a
Nata [24]

Answer:

There are present 5,5668 moles of water per mole of CuSO₄.

Explanation:

The mass of CuSO₄ anhydrous is:

23,403g - 22,652g = 0,751g.

mass of crucible+lid+CuSO₄ - mass of crucible+lid

As molar mass of CuSO₄ is 159,609g/mol. The moles are:

0,751g ×\frac{1mol}{159,609g} = 4,7052x10⁻³ moles CuSO₄

Now, the mass of water present in the initial sample is:

23,875g - 0,751g - 22,652g = 0,472g.

mass of crucible+lid+CuSO₄hydrate - CuSO₄ - mass of crucible+lid

As molar mass of H₂O is 18,02g/mol. The moles are:

0,472g ×\frac{1mol}{18,02g} = 2,6193x10⁻² moles H₂O

The ratio of moles H₂O:CuSO₄ is:

2,6193x10⁻² moles H₂O / 4,7052x10⁻³ moles CuSO₄ = 5,5668

That means that you have <em>5,5668 moles of water per mole of CuSO₄.</em>

I hope it helps!

5 0
3 years ago
How many milliliters of a 9.0 m h2so4 solution are needed to make 0.25 l of a 3.5 m h2so4 solution?
lorasvet [3.4K]
The rule that we will use to solve this problem is:
M2*V1 = M2*V2 where:
M1 is the initial concentration = 3.5 m
V1 is the initial volume = 0.25 l = 250 ml
M2 is the final concentration = 9 m
V2 is the final volume that we need to find

Substitute with the givens in the above equation to get V2 as follows:
3.5*250 = 9*V2
V2 = 97.2223 ml
7 0
3 years ago
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