I believe it’s 3 hours since every hour it’s 80km so 3x80 is 240 so it would be 3 hours.
The enthalpy change of the reaction is <u>-1347.8 kJ.</u>
<h3>What is the enthalpy change, ΔH, of the reaction?</h3>
The enthalpy change, ΔH, of the reaction is calculated from Hess's law of constant heat summation as follows:
Hess's law states that the enthalpy change of a reaction is the sum of the enthalpies of the intermediate reaction.
Given the reactions below and their enthalpy values;
1. X (s) + 12 O₂ (g)⟶ XO (s) ΔH₁ = −850.5 kJ
2. XCO₃ (s) ⟶ XO (s) + CO₂ (g) ΔH₂ = +497.3 kJ
The enthalpy change, ΔH, of the reaction whose equation is given below, will be:
X (s) + 12 O₂ (g) + CO₂ (g) ⟶ XCO₃ (s)
ΔH = ΔH₁ - ΔH₂
ΔH = − 850.5 kJ - (+497.3 kJ)
ΔH = -1347.8 kJ
Learn more about enthalpy change at: brainly.com/question/14047927
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Answer:
51.8 L is the new volume
Explanation:
In the two situations we have this relationship:
P ₁ . V₁ / T₁ = P₂ . V₂ / T₂
Let's convert the temperature to absolute values
T°K = T°C + 273
22.9°C + 273 = 295.9 K
44.5°C + 273 = 317.5 K
Let's convert now, the Torr to atm.
778 Torr . 1 atm / 760 Torr = 1.02 atm
Now we can replace:
3.4 atm . 14.5L / 295.9K = 1.02 atm . V₂ / 317K
(3.4 atm . 14.5L / 295.9K) . 317 K = 1.02 atm . V₂
( (3.4 atm . 14.5L / 295.9K) . 317 K ) / 1.02 atm = V₂ → 51.8 L
P ₁ . V₁ / T₁ = P₂ . V₂ / T₂ is derived from the Ideal Gases Law equation, and it is fulfilled when the moles of a gas, remains constant after the change of T°, pressure and volume.
1. minimize
2. not buy the insurance
3. too expensive in relation to the value of his vehicle
The correct answer is 2.99 helium atoms.
I hoped this helped!