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dedylja [7]
2 years ago
14

Chemistry: how does temperature relate to kinetic energy? pls answer in a short and easy way :D

Chemistry
2 answers:
ryzh [129]2 years ago
8 0

The temperature relate to kinetic energy by the energy of the particles in the sample

OverLord2011 [107]2 years ago
6 0

The hotter it is, the faster the atoms in something are moving.

pls give brainliest.

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The most unusual characteristic of Uranus is _____.
fiasKO [112]

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the axis is tilted at 98 degrees

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Uranus is blue, not green; it has an atmosphere of hydrogen and helium, not methane.  While it does have an icy cold temperature, that's not a very unusual characteristic for an outer planet.  However, the tilt of the axis is unusual; no other planet is tilted almost completely on its side!

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Does anyone know the answer?????​
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that should answer ur question

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3 years ago
Throughout the reflection, make sure you have a copy of the Student Guide and your data tables. Fill in the terms
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Convection, and boundaries

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3 years ago
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What is an isotope? atoms of the same element with different number of​
geniusboy [140]

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If you added 45,000 calories to water that was at 25 degrees C, and the ending temperature was 35 degrees C, how much water did
user100 [1]

<u>Answer:</u>

<em>4.5 L water we have in litres (L).</em>

<em><u></u></em>

<u>Explanation:</u>

Q=m\times c \times \Delta T

where

\Delta T = Final T - Initial T

Q is the heat energy in calories

c is the specific heat capacity (for water 1.0  cal/(g℃))  

m is the mass of water

Plugging in the values  

\\$45000 \mathrm{cal}=m \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times\left(35^{\circ} \mathrm{C}-25^{\circ} \mathrm{C}\right)$\\\\$45000 \mathrm{cal}=m \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times 10^{\circ} \mathrm{C}$\\\\$m=\frac{45000 \mathrm{cal}}{1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times 10^{\circ} \mathrm{C}}$\\\\$m=4500 \mathrm{g}$\\\\Density of water $=\frac{\text { mass }}{\text { volume }}$

So,

Volume of water = mass/density

\\\\=\frac{4500 \mathrm{g}}{\frac{1.09}{\mathrm{mL}}}=4500 \mathrm{mL}$$

=4.5 L (Answer)

6 0
3 years ago
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