C (s) + 2 H2 (g) = CH4 (g)
Empirical formula: Li4OH
Answer:
1 mole: 44.771 g
1 gram = 0.022 mole
Explanation:
Element: Li
Percentage by mass: 62.01%
Number of atoms: 4
Mass of atom;: 6.941
Element: O
Percentage by mass: 35.74%
Number of atoms: 1
Mass of atom: 15.9994
Element: H
Percentage by mass: 2.25%
Number of atoms: 1
Mass of atom: 1.00794
Answer:
Explanation:
Gold (111) Chloride:
AuCl₃
The oxidation state of gold is +3.
Chlorine is present in group seventeen and have seven valance electrons . Thus it accept one electron to complete the octet and show oxidation state -1.
When it react with gold(III) three chlorine atoms are combine with one gold atom to make compound overall neutral.
Calcium Carbonate:
CaCO₃
Carbonate formula is CO₃²⁻ . It means it carry -2 charge . Calcium is present in group two. It has two valance electrons and lose them to get complete octet thus shows +2 oxidation state.
When it combine with carbonate the overall compound is neutral because -2 and +2 charges cancel each other.
Hydrobromic Acid
HBr
Hydrogen has one electron while bromine has seven valance electrons. Bromine require one more electron to complete the octet. It react with hydrogen by sharing of one electron of hydrogen and form polar covalent compound.
Answer:
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Explanation:
So first we need to know what the formulas are:
Methane: 
Oxygen: 
Carbon Dioxide: 
Water: 
So then we follow the equation as specified in the question. Note that it does not need to be balanced, as the question states it wants the unbalanced equation:
→ 
This is the preliminary, unbalanced equation with the correct chemical formulas.
