one mole of sulfuric acid will contain 2 moles of hydrogen atoms. The molar mass of sulfuric acid is 98.0795 g/mol. This means that every mole of sulfuric acid has a mass of 98.0795 g. Since you're dealing with one mole of sulfuric acid, it follows that you will also be dealing with two moles of hydrogen.
First convert 0.163 grams of N2O to mol by dividing it with
the molecular weight. The molecular weight of N2O is 44 grams/mol. The answer
would be 3,79x10^-3. Then multiply it with 2 since there are 2 Nitrogen in one
mole of N2O. Therefore, there are 7.41x10^-3 moles of Nitrogen.
Reactant: <span>Cd(NO^3)^2+(aq)+H^2S(g)
</span>Product: <span>Cds(s)+2HNO^3(aq)</span>
Ions will combine to form compounds through the transfer of electrons. Hope this helps!
<span>0.228 g
The balance formula for the reaction between SrH2 and H2O is
SrH2(s) + 2 H2O(l) ==> Sr(OH)2(s) + 2 H2(g)
So for every mole of SrH2 used, 2 moles of hydrogen gas, or 4 moles of hydrogen atoms are released. So let's calculate the molar mass of SrH2 and H2O so see what the limiting reactant is.
strontium = 87.62
Hydrogen = 1.00794
Oxygen = 15.999
Molar mass of SrH2 = 87.62 + 2 * 1.00794 = 89.63588 g/mol
Molar mass of H2O = 2 * 1.00794 + 15.999 = 18.01488 g/mol
Moles of SrH2 = 5.06 g / 89.63588 g/mol = 0.056450609 mol
Moles of H2O = 4.34 g / 18.01488 g/mol = 0.240911957 mol
Looking at the balanced formula, for every mole of SrH2, it takes 2 moles of H2O. So the limiting reactant will be the SrH2. And for every mole of SrH2 used, we get 4 moles of hydrogen atoms. So
4 * 0.056450609 mole * 1.00794 g/mole = 0.227595307 g
Since we only have 3 significant figures, round the result to 3 figures, giving
0.228 g</span>
