Answer:
Explanation:
<u>Frictional Force
</u>
When the car is moving along the curve, it receives a force that tries to take it from the road. It's called centripetal force and the formula to compute it is:
The centripetal acceleration a_c is computed as
Where v is the tangent speed of the car and r is the radius of curvature. Replacing the formula into the first one
For the car to keep on the track, the friction must have the exact same value of the centripetal force and balance the forces. The friction force is computed as
The normal force N is equal to the weight of the car, thus
Equating both forces
Simplifying
Substituting the values
fluid friction<span> occurs when an object moves through a liquid or gas. the force needed to overcome </span>fluid friction <span>is usually less then that needed to overcome </span>sliding friction<span>. the </span>fluid<span> keeps the surface from making direct contact and thus </span>reducing friction<span>.</span>
For the answer to the question above, <span>at the end, the KE = 1/2mv^2 = (1/2)(2000)(2^2) = 4000 J This must equal the net work acting on the car. W=Fd The net force is 1140-950= 190N. so, d=W/F = 4000/190 = 21.05 m
I hope my answer helped you.</span>
The initial compression of the spring is determined as 0.54 m.
<h3>What is the compression of the spring?</h3>
The compression of the spring is determined by applying the principle of conservation of linear momentum as follows;
E = U
mgh = ¹/₂kx²
2mgh = kx²
x² = 2mgh/k
x = √(2mgh/k)
where;
- m is the mass of the projetcile
- h is the height
- k is the spring constant = 0.07 N/cm = 7 N/m
- x is the compression of the spring
x = √(2 x 0.021 x 9.8 x 5)/7)
x = 0.54 m
Learn more about compression of spring here: brainly.com/question/2114706
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