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olga_2 [115]
3 years ago
9

(No links, if you aren’t gonna answer here don’t answer at all.)

Physics
1 answer:
Liula [17]3 years ago
6 0

Answer:

D. Atoms with eight valence electrons usually do not gain or lose

electrons.

Explanation:

An atom can be defined as the smallest unit comprising of matter that forms all chemical elements. Thus, atoms are basically the building blocks of matters and as such defines the structure of a chemical element.

Generally, these atoms are typically made up of three distinct particles and these are protons, neutrons and electrons.

Valence electrons can be defined as the number of electrons present in the outermost shell of an atom. Valence electrons are used to determine whether an atom or group of elements found in a periodic table can bond with others. Thus, this property is typically used to determine the chemical properties of elements.

Based on the octet rule which states that atoms of chemical elements gain, lose or share electrons so as to have eight (8) electrons in their valence shell. Therefore, atoms of chemical elements bond in order to attain the electronic configuration of a noble gas i.e a full valence shell which comprises of eight (8) electrons.

This ultimately implies that, atoms with eight valence electrons usually do not gain or lose electrons because they're noble gas.

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A certain parallel-plate capacitor is filled with a dielectric for which κ = 6.56. The area of each plate is 0.0830 m2, and the
mafiozo [28]

Answer:

4.86\times 10^{-7}\ J

Explanation:

Given:

Dielectric of the medium between the plates (k) = 6.56

Area of eac plate (A) = 0.0830 m²

Separation between the plates (d) = 1.95 mm = 0.00195 m [1 mm = 0.001 m]

Maximum electric field (E_{max}) = 202 kN/C = 202000 N/C [1 kN = 1000 N]

Permittivity of space (ε₀) = 8.854 × 10⁻¹² F/m

The maximum potential difference across the plates of the capacitor is given as:

V_{max}=E_{max}d\\\\V=(202000\ N/C)(0.00195\ m)\\\\V=393.9\ V

Now, capacitance of the capacitor is given as:

C=\dfrac{k\epsilon_0A}{d}\\\\C=\frac{6.56\times 8.854\times 10^{-12}\ F/m\times 0.0830\ m^2}{0.00195\ m}\\\\C=2.47\times 10^{-9}\ F

The maximum energy stored in the capacitor is given as:

U_{max}=\frac{1}{2}CV_{max}^2\\\\U_{max}=\frac{1}{2}\times (2.47\times 10^{-9}\ F)\times  393.9\ V\\\\U_{max}=4.86\times 10^{-7}\ J

Therefore, the maximum energy that can be stored in the capacitor is 4.86\times 10^{-7}\ J

6 0
2 years ago
Which of the following is the BEST example of a goal
kvasek [131]
I will run 2 miles three times a week for 4 weeks.
7 0
3 years ago
Which statement best describes why electrons are typically not included when determining the mass of an atom?
Ede4ka [16]
<span>The protons and neutrons are much more massive than the electrons.
</span>
The electrons are simply too small to really change the mass, so they aren't counted.
4 0
2 years ago
Read 2 more answers
How fast should the platform move, vp, for the person to detect a beat frequency of 7.00 hz ? take the speed of sound to be 344
NeX [460]
<span>Delta(f) =f0 * v_rel/c , where v_rel is the relative velocity between source and observer. The source is moving at a speed v but the sound bounced off the wall and the receiver is moving toward it too. So, Delta(f) = f0 (2 V) / c Hence V = c Delta(f) /(2 f0)= 344 m/s * (7.00Hz/(2*245Hz)) =4.91 m/s</span>
7 0
3 years ago
Find the intensity i of the sound waves produced by one 60-w speaker at a distance of 1.0 m.
Kipish [7]

Answer:

the intensity of the sound waves produced by one 60-w speaker at a distance of 1.0 m is 60 w/m²

Explanation:

Intensity of sound , I, is given as;

I  = P/A

Where;

P is the power through an area = 60-w

A is the area = ?

A = 1.0m × 1.0m = 1.0 m²

I = 60-w / 1.0 m²

I = 60 w/m²

Therefore, the intensity of the sound waves produced by one 60-w speaker at a distance of 1.0 m is 60 w/m²

8 0
3 years ago
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