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amm1812
3 years ago
9

Consider separate samples of water and carbon dioxide, each with the same mass. Which contains the greater number of molecules?

Chemistry
1 answer:
Ahat [919]3 years ago
7 0

Answer: The sample that contains the greater number of molecules is water.

Explanation: To calculate the number of molecules, it is used the Avogadro's number ( 6.02*10^{23} particles/molecules). So, considering that the mass to water and carbon dioxide is 1g (it can be any other number), the relationship between moles and molar weight is:

moles =\frac{mass}{molar weight}

To water: moles = \frac{1g}{18 g/mol} = 0.05 moles.

Therefore,

1 mol ---- 6.02*10^{23} molecules

0.05 moles ---- x

x = 0.30*10^{23} molecules of water.

To carbon dioxide: moles = \frac{1g}{44 g/mol} = 0.02 moles.

Therefore,

1 mol ---- 6.02*10^{23} molecules

0.02 moles ---- y

y = 0.12*10^{23} molecules of carbon dioxide.

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Option B. PV = nRT.

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From the above,

C = PV / T. (1)

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C = nR

Substituting the value of C into equation (1), we have:

C = PV / T

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2 years ago
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Michelle is trying to find the average atomic mass of a sample of an unknown
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The average atomic mass of her sample is 114.54 amu

Let the 1st isotope be A

Let the 2nd isotope be B

From the question given above, the following data were obtained:

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The average atomic mass of the sample can be obtained as follow:

Average \: atomic \: mass \:  =  \frac{mass \: of \: A \times A\%}{100}  + \frac{mass \: of \: B \times B\%}{100}  \\  \\ Average \: atomic \: mass \:  =  \frac{113.6459\times 59.34}{100} + \frac{115.8488\times 40.66}{100} \\  \\ Average \: atomic \: mass \:  = 114.54 \: amu  \\  \\

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Learn more about isotope: brainly.com/question/25868336

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