The element which is oxidized in the reaction below
that is
Fe(Co)5 (l) + 2 Hi (g)= Fe (CO)4 i2(s) +Co (g)+H2 (g) is
Fe this is because fe in Fe(CO)5 compound move from oxidation state of Positive five (5^+) to oxidation state of positive six ( 6^+) in Fe(CO)4i2 compound. fe is oxidized by Hi while Hi itself is reduced by Fe,therefore Fe act as a reducing agent
Answer:
Anemometer. An anemometer is a type of weather instrument that measures wind speed.
Answer:
744.9 mmHg ≅ 745 mmHg
Explanation:
The base to solve this, is the Ideal Gases Law. The mentioned formula is:
P . V = n . R . T
To compare two situations, we can propose:
For the first situation P₁ . V₁ = n₁. R . T₁
For the second situation P₂ . V₂ = n₂ . R . T₂
As the sample has the same moles and R is a constant value, we can avoid them so: (P₁ . V₁) / T₁ = (P₂ . V₂) / T₂
We need to make Tº unit conversion:
25ºC + 273 = 298K
We replace data → (370 mL . 1020 mmHg) / 298K = (P . 510 mL) / 300 K
(377400 mL.mmHg / 298K) . 300 K = P . 510 mL
379932.8 mL . mmHg = P . 510 mL
(379932.8 mL . mmHg) / 510 mL = P → 744.9 mmHg
Answer:
The anion of the compound is b CH3COO-
Explanation:
The compound cupric acetate Cu(CH3COO)2 undergo dissociation to form cupric ion Cu2+ and Acetate anion(CH3COO-)
Cu(CH3COO)2⇒ Cu2+ + CH3COO-
From the above equation it can be stated that the anion of Cu(CH3COO)2 is CH3COO-.
This is pretty easy lol.... AS and AR
