Mass of KCl= 1.08 g
<h3>Further explanation</h3>
Given
1 g of K₂CO₃
Required
Mass of KCl
Solution
Reaction
K₂CO₃ +2HCl ⇒ 2KCl +H₂O + CO₂
mol of K₂CO₃(MW=138 g/mol) :
= 1 g : 138 g/mol
= 0.00725
From the equation, mol ratio K₂CO₃ : KCl = 1 : 2, so mol KCl :
= 2/1 x mol K₂CO₃
= 2/1 x 0.00725
= 0.0145
Mass of KCl(MW=74.5 g/mol) :
= mol x MW
= 0.0145 x 74.5
= 1.08 g
P1v1/t1 = p2t2/t2
p is constant
v1=600, t1 =20c=293K
v2=?, t2=60c=333K
temperature must be in Kelvin
do the math
1) 1.8 micrograms(least)
2) 1.8 grams
3) 1.8 kilograms(greatest)
Answer:
reactivity:very reactive,less reactive
density:float in water,sink in water
melting and boiling point:low,high
colour of salts: colourless,often coloured
Option B. <span>Rb2O + Cu(C2H3O2)2 → 2RbC2H3O2 + CuO is the correct answer. HOPE IT HELPS</span>
