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3 years ago

Which term defines the distance from the focal point to either a lens or a mirror

Chemistry

1 answer:

nikklg [1K]3 years ago

3 0

The focal length, like you said it's the distance between the FOCAL point and the mirror.

Hope this helps.... :)

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A 642 mL sample of oxygen gas at 23.5°C and 795 mm Hg, is heated to 31.7°C and the volume of the gas expands to 957 mL. What is

Ratling [72]

We can use the combined gas law equation to find the new pressure of the gas.
$\frac{P1V1}{T1} = \frac{P2V2}{T2}$
where P - pressure
V - volume
T - temperature
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
P1 - 795 mm Hg x 0.0013 atm/ mm Hg = 1.033 atm
T1 - 23.5 °C + 273 = 296.5 K
T2 - 31.7 °C + 273 = 304.7 K
substituting the values in the equation
$\frac{1.033 atm *642 mL}{296.5K}= \frac{P*957mL}{304.7K}$
P = 0.712 atm
the answer closest to this value is A) 0.723 atm
therefore answer is
<span>A) 0.723 atm</span>

8 0

4 years ago

The anesthetic procaine hydrochloride is often used to deaden pain during dental surgery. the compound is packaged as a 10.% sol

vichka [17]

10% solution means= $\frac{10g}{100mL}$

= $\frac{0.1g}{1mL}$

= 100 mg/mL

If the dentist inject 0.3 mL, that is equal to 0.3× 100 mg.

If the dentist inject 0.3 mL, that is equal to 30 mg.

So, as anesthetic procaine hydrochloride is often used to deaden pain during dental surgery. the compound is packaged as a 10.% solution (by mass; d = 1.0 g/ml) in water. When our dentist injects 0.30 ml of the solution, 30 mg of procaine hydrochloride (in milligrams) is injected.

6 0

3 years ago

when a log of wood burns, it undergoes a _______. a. physical change. b. chemical change. c. physical and a chemical change. d.

statuscvo [17]

B. Chemical change is the answer!<span />

3 0

3 years ago

Read 2 more answers

A 10.1 g sample of NaOH is dissolved in 250.0 g of water in a coffee-cup calorimeter. The temperature increases from 23.0 °C to

givi [52]

Hey there!:

moles of NaOH = 10.1 / 40 = 0.2525

heat = ΔH x moles

= 44.4 x 0.2525

= 11.21 kJ

total mass = 10.1 + 250 = 260.1 g

Q = m Cp dT

11211 = 260.1 x 4.18 x dT

dT = 10.3

T2 = 10.3 + 23 = 33.3 °C

temperature = 33.3 ºC°

Hope this helps!

6 0

3 years ago

Read 2 more answers

Pls help me with my chemistry finals test.

Nutka1998 [239]

What do you need help with? Can you specify?

3 0

3 years ago