<span>Ionization energy (IE) is the amount of energy required to remove an electron.
If you observe the IEs sequentially, there is a large gap between the 2nd and 3rd. This suggests it is difficult to remove more than 2 two electrons. Elements that lose two electrons to become more stable are found in the Group 2A (2 representing the number of electrons in the outermost valence shell).</span>
C) the nucleus. Hope this helps :)
Answer:
P = 133.4 atm
Explanation:
Given data:
Mass of helium = 988 g
Volume = 45.0 L
Temperature = 23°C (23+273= 296 K)
Pressure of cylinder = ?
Solution:
Number of moles of helium:
Number of moles = mass/ molar mass
Number of moles = 988 g/ 4 g/mol
Number of moles = 247 mol
Pressure:
PV = nRT
P = nRT/V
P = 247 mol × 0.0821. atm. L/mol. K × 296 K / 45 L
P = 6002.5 / 45 L
P = 133.4 atm
<span>The choices are as follows:
h2o + 2o2 = h2o2
fe2o3 + 3h2 = 2fe + 3h2o
al + 3br2 = albr3
caco3 = </span><span>cao + co2
The correct answers would be the second and the last option. The equations that are correctly balanced are:
</span> fe2o3 + 3h2 = 2fe + 3h2o
caco3 = cao + co2
To balance, it should be that the number of atoms of each element in the reactant and the product side is equal.
Volume can be measured in cubic centimetres (which is the small 3 next to the unit and is higher)