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Calculate the vapor pressure of a solution of 32.5 g of glycerol (C3H8O3) in 500.0 g of water at 25°C. The vapor pressure of wat

Luba_88 [7]

The vapor pressure is obtained as 23.47 torr.

<h3>What is the vapor pressure?</h3>

Given that; p = x1p°

p = vapor pressure of the solution

x1 = mole fraction of the solvent

p° = vapor pressure of the pure solvent

Δp = p°(1 - x1)

Δp =x2p°

Δp = vapor pressure lowering

x2 = mole fraction of the of the solute

Number of moles of glycerol = 32.5 g/92 g/mol = 0.35 moles

Number of moles of water = 500.0 g/18 g/mol = 27.8 moles

Total number of moles = 0.35 moles + 27.8 moles = 28.15 moles

Mole fraction of glycerol = 0.35 moles/28.15 moles = 0.012

Mole fraction of water = 27.8 moles/28.15 moles =0.99

Δp = 0.012 * 23.76 torr

Δp = 0.285 torr

p1 = p° - Δp

p1 = 23.76 torr - 0.285 torr

p1 = 23.47 torr

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5 0

1 year ago

What type of bond is this combination likely to form

kari74 [83]

Answer:

A combination is certainly possible, but you should not take formal charges so literally

Normally, when a covalent bond is found, the two atoms both bring in one electron. As you identify correctly, in the case of nitric acid that would not be possible completely. If you draw the different possible resonance structures, the most likely structure has a single bond between the nitrogen and an oxygen where the oxygen has 3 lone pairs and both electrons in the bond are donated by the nitrogen. This makes the nitrogen "positive" and that oxygen "negative", but in fact the electrons move more freely in the molecule and charges are more distributed. You will not be able to find "the negatively charged" oxygen atom.

Explanation:

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4 0

3 years ago

Draw the Lewis structure for the Se and 2 H atoms.

fomenos

When drawing lewis dot diagram structure we consider the number of valence electrons of the atom.Se has six valence electrons since it is in group six thus it Lewis dot diagram is as follows
..
: Se:
Hydrogen is in group one hence has one valence electron.The lewis dot diagram for 2H is therefore
H:H

3 0

3 years ago

Read 2 more answers

Q2.Which is true about potassium?

Olenka [21]

$\bf \LARGE\rightarrow{Very \: reactive}$