The dance that was being created was Hip Hop dance!
Answer:
The acceleration is
and the distance covered is 97.17 m.
Explanation:
Given that,
Initial speed of an automobile, u = 60 km/hr = 16.67 m/s
Final speed of an automobile, v = 80 km/hr = 22.2 m/s
Time, t = 5 s
We need to find the acceleration of the car and the distance traveled in this 5 sec interval. Let a is the acceleration. Using the definition of acceleration as :

Let d is the distance covered. Using the third equation of motion to find it as follows :

So, the acceleration is
and the distance covered is 97.17 m.
Explanation:
In positional number system,
1. each symbol represents different value depending on the position they occupy in a number.
2. In positional number system, each system has a value that relates to the number directly next to it. The total value of a positional number is the total of the resultant value of all positions.
3. Example: 12 can be 1 x 10 + 2 x 1, 10 + 2= 12
whereas in Non-Positional number
1. In non-positional number system, each symbol represents the same value regardless of its position
2. In non-positional number system each symbol represents a number with its own place value.
3. Example: Roman number system where I for 1, II for 2 etc.
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Answer:

Explanation:
<u>Accelerated Motion
</u>
When a body changes its speed at a constant rate, i.e. same changes take same times, then it has a constant acceleration. The acceleration can be positive or negative. In the first case, the speed increases, and in the second time, the speed lowers until it eventually stops. The equation for the speed vf at any time t is given by

where a is the acceleration, and vo is the initial speed
.
The train has two different types of motion. It first starts from rest and has a constant acceleration of
for 182 seconds. Then it brakes with a constant acceleration of
until it comes to a stop. We need to find the total distance traveled.
The equation for the distance is

Our data is

Let's compute the first distance X1


Now, we find the speed at the end of the first period of time


That is the speed the train is at the moment it starts to brake. We need to compute the time needed to stop the train, that is, to make vf=0



Computing the second distance


The total distance is


