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user100 [1]
3 years ago
14

A fish can travel 30km/h in still water. How long will it take to arrive 12km downstream in a river flowing 6km/h?

Physics
1 answer:
kodGreya [7K]3 years ago
8 0
30 + 6 = 36

36/12 = 3



So, it would take it 3 hours to go 12 kms downstream.



Note that we added 30 and 6 because it was going downstream. If it was going upstream, then we would have had to subtract.
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frozen [14]

Answer:

when switch is off no electricity will flow and then the circuit is called an open circuit

Explanation:

Electricity will not flow in open circuit

7 0
1 year ago
A 50.0-kg box is being pulled along a horizontal surface by means of a rope that exerts a force of 250 n at an angle of 32.0° ab
Phoenix [80]
According to Newton's second law, the resultant of the forces acting on the box is equal to the product between its mass and its acceleration:
\sum F = ma (1)

we are only concerned about the horizontal direction, so there are only two forces acting on the box in this direction:
- the horizontal component of the force exerted by the rope, which is equal to
F_x = F cos \theta = (250N)(\cos 32.0^{\circ} )=212.0 N
- the frictional force, acting in the opposite direction, which is equal to
F_f = \mu mg=(0.350)(50.0 kg)(9.81 m/s^2)=171.7 N

By applying Newton's law (1), we can calculate the acceleration of the box:
F_x - F_f = ma
a= \frac{F_x - F_f}{m}= \frac{212.0 N-171.7 N}{50.0 kg} =0.81 m/s^2

6 0
3 years ago
Light travels at a constant speed of about 300,000 km/s. This speed is referred to as the speed of light. A light year is the di
Rama09 [41]

Based on the information in the question, a light year is the distance traveled light in one year. Then if the light from the star Centauri takes 4.2 years to reach the earth, then its distance from earth is 4.2 light years.

7 0
2 years ago
Read 2 more answers
What is the potential difference when the current in a circuit is 5mA and resistance is 30 Ohms
Mashcka [7]

<h2>\bf{ \underline{Given:- }}</h2>

\sf• \: The \:  current \:  in \:  a \:  circuit \:  is  \: 5 \: amps.  \: and  \: resistance \:  is \:  30 \:  Ohms.

\\

<h2>\bf{ \underline{To \:  Find :- }}</h2>

\sf{• \:  The  \: Potential  \: Difference. }

\\

\huge\bf{ \underline{ Solution:- }}

\sf According  \: to  \: the  \: question,

\sf•  \: Current \:  (I) = 5  \: Amps.

\sf• \:  Resistance  \: (R) = 30 \:  Ω

\sf{Potential \:  difference  \: means  \: Voltage \: ( V).}

\sf{We \:  know \: that, }

\bf \red{ \bigstar{ \: V = IR }}

\rightarrow \sf V =5 \times 30

\rightarrow \sf V =150

\\

\sf \purple{Therefore, \:  the \:  potential  \: difference  \: is  \: 150  \: v \: .}

4 0
3 years ago
A star produces 2x10^26 watts. how much energy does it lose every minutes
Step2247 [10]

Answer:

Energy loss per minute will be 120\times 10^{26}j

Explanation:

We have given the star produces power of 2\times 10^{26}W

We know that 1 W = 1 J/sec

So 2\times 10^{26}W=2\times 10^{26}J/sec

Given time = 1 minute = 60 sec

So the energy loss per minute =2\times 10^{26}\times 60=120\times 10^{26}j

We multiply with 60 we have to calculate energy loss per minute

7 0
3 years ago
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