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2 years ago

9

The inventor of the photographic process in which a photograph produced without a negative by exposing objects to light on light

sensitive paper, is named _____________
a. Man Ray
c. Dorothea Lange
b. Richard Avedon
d. Pablo Picasso

2 answers:

Bad White [126]2 years ago

8 0

Answer:

it's A man ray as in one of spongebob's evil villains

i think

.w.

Nikolay [14]2 years ago

7 0

<span>A. Man Ray --------------------</span>

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a roller coaster begins at the top of a hill if it acelerates at the rate of 2 m/s2 and has a mass of 2000 kg what net force is

AlladinOne [14]

Answer:

$\boxed {\boxed {\sf 4000 \ Newtons }}$

Explanation:

Force can be found by multiplying the mass by the acceleration.

$F=m*a$

The mass of the roller coaster is 2000 kilograms and the acceleration is 2 meters per second squared.

$m= 2000 \ kg \\a= 2 \ m/s^2$

Substitute the values into the formula.

$F= 2000 \ kg * 2 \ m/s^2$

Multiply.

$F= 4000 \ kg*m/s^2$

1 kg*m/s² is equal to 1 N
Therefore our answer of 4000 kg*m/s² is equal to 4000 Newtons

$F= 4000 \ N$

The net force acting on the roller coaster is <u>4000 Newtons.</u>

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2 years ago

Since the moon has less mass than the earth what happens to objects on the moon

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When you drop an object on the moon, it falls to the ground.
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If you were told an atom was an ion, you would know the atom must have a

Effectus [21]

The atom must have gained 1 or more electrons or must have lost 1 or more electrons.

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3 years ago

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An unbalanced force gives a 2.00 kg mass an acceleration of 5.00 m/s? What is the force applied to the object?

valentinak56 [21]

Answer:

10N

Explanation:

Equation: ΣF = ma

Fapp = ma

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1 year ago

The net horizontal force on a car is 981 N. The car has a mass of 1550 kg and the force is applied when the car has a speed of 2

viktelen [127]

Answer:

Distance, d = 778.05 m

Explanation:

Given that,

Force acting on the car, F = 981 N

Mass of the car, m = 1550 kg

Initial speed of the car, v = 25 mi/h = 11.17 m/s

We need to find the distance covered by car if the force continues to be applied to the car. Firstly, lets find the acceleration of the car:

$F=ma\\\\a=\dfrac{F}{m}\\\\a=\dfrac{981}{1550}\\\\a=0.632\ m/s^2$

Let d is the distance covered by car. Using second equation of motion as :

$d=ut+\dfrac{1}{2}at^2\\\\d=11.17\times 35+\dfrac{1}{2}\times 0.632\times (35)^2\\\\d=778.05\ m$

So, the car will cover a distance of 778.05 meters.

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3 years ago