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Simora [160]
3 years ago
13

Which can be replenished?

Physics
1 answer:
Varvara68 [4.7K]3 years ago
5 0

Answer: B.

Explanation:

A replenishable resource is the one which can be produced by natural cycle and can be reused. Such a resource is called renewable resource. The renewable resource can be renewed with due course of time.

Option B is the correct option as it includes the forest. The forest when clear cut for wood or any other need can be grown again by using seeds of the same kind of plants used to grow earlier or by planting plantlets so as to restore the forest again. It is an example of replenishable renewable resource.

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A parallel-plate capacitor has a plate separation of 1.5 mm and is charged to 600 V. If an electron leaves the negative plate, s
DiKsa [7]

GIven data:

Distance between the plates = 1.5 mm

Potential difference V = 600V

Charge on electron q = -1.6× 10^{-19} C

mass on electron = m = 9.1×10^{-31} Kg

Solution:

First we will find the change in potential energy of the charge while moving through the potential difference of 600V.

ΔU = qΔV

     = (-1.6×10^{-19})(600)

     = -9.6×10^{-19}J

By the law of conservation of mechanical energy, as there is no external force acting, so the sum of the kinetic and potential energies will be a constant.

K + U = E

ΔK + ΔU = 0

ΔK = -ΔU

1/2mv² = -ΔU

v² = -2ΔU/m

   = \frac{-2(-9.6*10^{-19}) }{9.1*10^{-31} }

v = \sqrt{2.11*10^{14} }

v = 1.45×10^{7} m/s  

8 0
3 years ago
Read 2 more answers
Does wind have atoms and molecules in int
satela [25.4K]
All forms of matter are comprised of atoms. Wind in itself is the movement of particles(air). Wind does not have particles since it is an action and not a form of matter.
4 0
4 years ago
Can someone help me?
stepladder [879]
T=0-15.5/-0.392
=39.5m/s

8 0
4 years ago
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A satellite is orbiting the earth just above its surface. The centripetal force making the satellite follow a circular trajector
Pavlova-9 [17]

Answer:

v=7905m/s

t=5063s

Explanation:

A satellite is orbiting the earth just above its surface. The centripetal force making the satellite follow a circular trajectory is just its weight, so its centripetal acceleration is about 9.81 m/s2 (the acceleration due to gravity near the earth's surface). If the earth's radius is about 6370 km, how fast must the satellite be moving? How long will it take for the satellite to complete one trip around the earth?

The weight of the satellite is the centripetal force, so:

W=mg=F_{cp}=ma_{cp}=m\frac{v^2}{r}

Which means: g=\frac{v^2}{r}

We can calculate then the velocity:

v=\sqrt{gr}=\sqrt{(9.81m/s^2)(6370000m)}=7905m/s

For calculating how long will it take for the satellite to complete one trip around Earth we consider that the distance of the trip is the circumference of the orbit. This is calculated as C=2\pi r.

Since velocity is v=d/t, we have:

t=d/v=C/v=2\pi r/v=\frac{2\pi 6370000}{7905m/s} =5063s

5 0
3 years ago
20. Evaluating Data You are looking at a star through a telescope in January.
REY [17]
It is c I took the test
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3 years ago
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