The pencil rotates about an axis perpendicular to the plane of the figure. which of the labeled points is the point that the axi
2 answers:
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Answer:
a = 1.055 x 10¹⁷ m/s²
Explanation:
First, we will find the force on electron:
where,
F = Force = ?
E = Electric Field = 6 x 10⁵ N/C
q = charge on electron = 1.6 x 10⁻¹⁹ C
Therefore,
F = 9.6 x 10⁻¹⁴ N
Now, we will calculate the acceleration using Newton's Second Law:
where,
a = acceleration = ?
m = mass of electron = 9.1 x 10⁻³¹ kg
therefore,
<u>a = 1.055 x 10¹⁷ m/s²</u>
Answer and Explanation: A charge exerts a force over another charge even if they are very far apart. This force is called <u>Electrostatic</u> <u>Force</u>.
If the two charges have the same sign, e.g. both aare positive, the force between them is opposite. If they have opposite sign, the force is towards each other. In other words, for electrostatic force, equal charges repel and different charges attract.
So,
1. If Q2 and Q3 have opposite signs, it is TRUE force in Q2 will go the left;
2. If the 2 are negative, they have the same sign, so it's FALSE force is to the right;
Sentences 3 and 4 are also TRUE due to the reasons described above;
5. If the charges have opposite signs, it means force is towards each other, or, to the right, so the sentence is TRUE;
1. Force is directly proportional to charges in Coulomb [C] and inversely proportional to distance squared in [m]:
where k is a constant that equals 9 x 10⁹ N.m²/C²
Calculating force between 1 and 2:
N
Force between 2 and 3:
N
Total force is the net force. Since Q2 is negative and the others are positive, force of 2 related to 1 is to left and related to 3 is to the right. Therefore, total force is the difference between those two forces:
N
The total force on Q2 is 2175.61 x 10⁻³ N
2. For net force to be 0, . Suppose distance from 1 to 3 is x, then from 2 to 3 is
Calculating:
roots = 0.14 or -1.35
Solving quadratic equation gives 2 roots, but one of the roots is negative. As distance is a measure that cannot be negative, the solution is x = 0.14.
The distance of Q3 relative to Q1 is 0.14 m
I’m sorry if i took up a lot of space, hope this is a valid approximate answer
