Answer:

Explanation:
Given:
- mass of solid disk,

- radius of disk,

- force of push applied to disk,

- distance of application of force from the center,

<em>For the condition of no slip the force of static friction must be greater than the applied force so that there is no skidding between the contact surfaces at the contact point.</em>

where:
= static frictional force




Each BB 0.349 grams and 5.386 grains. 349 mg & 5.386 grains each steel BBs.
Answer:
2.295 eV
Explanation:
maximum wavelength, λ = 542 nm = 542 x 10^-9 m
The work function of the metal is defined as the minimum amount of energy falling on the metal so that the photo electrons just ejects the surface of metal.

where, h is the Plank's constant and c be the speed of light
h = 6.634 x 10^-34 Js
c = 3 x 10^8 m/s


Wo = 2.295 eV
Thus, the work function of this metal is 2.295 eV.
The answer is 10,560 Joules or 1.1*10^4
Explanation:
Step 1: Calculate
The equation for Kinetic Energy is
Kinetic energy=.5 times Mass times Velocity²
KE=.5*m*v²
so we plug in our numbers
KE=.5*600*35.2²
This works out to be 10,560 Joules or 1.1*10^4