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faust18 [17]
2 years ago
9

How does the resting energy expenditure change as a person ages

Physics
1 answer:
Lady bird [3.3K]2 years ago
6 0

Answer:

Resting energy expenditure (REE) decreases from young to old age by 1% to 2% per decade [1]. This is partly explained by age-related decreases in fat free mass (FFM) [2]. FFM accounts for 50%–70% of the variance in REE [3,4,5].Explanation:

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What is an experience from everyday life that appears to support the geocentric model
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<span>One everyday life experience that seems to support the geocentric model is the rising and setting of the Sun and Moon. The Moon rises and falls because it does revolve around the Earth and so it is easy to assume the same is true for the Sun.</span>
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3 years ago
3. Study 1 differed from Study 2 in which of the follow-
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4 0
2 years ago
A golf ball is struck at 75 m/s at an angle of 60 degrees. What is the
Gnesinka [82]

Answer:

v_x=37.50

Explanation:

The rectangular components of a vector \vec v having a magnitude v and angle θ are:

v_x=v\cos\theta

v_y=v\sin\theta

The golf ball has an initial speed of 75 m/s at an angle of 60 degrees.

The variables of the equations have the values:

v = 75 m/s

θ = 60°

Substituting into the formula:

v_x=75\cos 60^\circ

v_x=75\cdot 0.5

v_x=37.5~m/s

Without specifying units and with precision to the hundredths place:

\mathbf{v_x=37.50}

7 0
3 years ago
What is the final position of the object if its initial position is x = 0.40 m and the work done on it is equal to 0.21 J? What
r-ruslan [8.4K]

Answer:

a) Final position is x = 0.90 m

b) Final position is x = 0.133 m

Explanation:

The workdone between two points is usually approximated as the area under the force-distance curve between those two points.

From the graph,

As at the initial position, x = 0.40 m and the corresponding F = 0.8 N,

The area from that point onwards up to the end of that particular bar = 0.8 (0.5 - 0.4) = 0.08 J

The next bar has force = 0.4 N and the width of the bar = (0.75 - 0.50) = 0.25 m

Work done under this bar = 0.4 × 0.25 = 0.1 J

Total work done from the starting position up to this point now = 0.08 + 0.1 = 0.18 J, still less than 0.21 J

So, the final position has to be on the last bar. Let the position be x. The force on the last bar = 0.2 N

0.21 = 0.18 + 0.2 (x - 0.75)

0.03 = 0.2x - 0.15

0.2x = 0.18

x = 0.9 m

Therefore, the final position of the object, to do 0.21 J worth of work, starting from x = 0.4 m is 0.90 m.

b) For this part, negative work is done, this means, we will move in the negative direction to try and trace this total work done.

From the starting point where the initial position is 0.40 m, the force here is 0.80 N

The workdone under this bar to the left is

The workdone = 0.8 (0.25 - 0.4) = - 0.12 J

Since we're tracing -0.19 J, the final position has to be on the last bar (on the left), Let the position be x. The force on the last bar on the left (could also be referred to as the first bar) = 0.60 N

- 0.19 = -0.12 + 0.6 (x - 0.25)

-0.07 = 0.6x - 0.15

0.6x = 0.08

x = (0.08/0.6) = 0.133 m

Therefore, the final position of the object, after doing -0.19 J worth of work, starting from x = 0.4 m is 0.133 m.

Hope this Helps!!!

4 0
3 years ago
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